Question

A beam of protons is moving in the x direction with a speed of 10.6 km/s through a region in which the electric field is perpendicular to the magnetic field. The beam is not deflected in this region. If the magnetic field has a magnitude of 0.802 T and points in the y direction, find the magnitude and direction of the electric field. Give the x, y, and z component of the electric field.

Answer 1

Answer:

E= 8501.2

Explanation:

Given Data;

Speed = 10.6 km/s = 10.6*10^3 m/s

Magnitude = 0.802 T

The magnitude of the electric field is calculated using the formula;

q E = q v B

E = v B

   = 10.6 *10^3 * 0.802

   = 8501.2

The direction of the electric field will point along the negative z-axis