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Answer:
Speed=1.633 m/s
Force= 20 N
Explanation:
Ideally, hence
where v is the speed of collar, m is the mass of collar, k is spring constant and s is the displacement.
In this case, s=100-0=100mm=0.1m since 1 m is equivalent to 1000mm
k is given as 200 N/m and mass is 0.75 Kg
Substituting the given values
Therefore, <u>the speed is 1.633 m/s</u>
The sum of vertical forces is given by mg where g is acceleration due to gravity and it's value taken as
Therefore,
The sum of forces in normal direction is given by therefore
Therefore, <u>normal force on the rod is 20 N</u>
Answer:
P=361.91 KN
Explanation:
given data:
brackets and head of the screw are made of material with T_fail=120 Mpa
safety factor is F.S=2.5
maximum value of force P=??
<em>solution:</em>
to find the shear stress
T_allow=T_fail/F.S
=120 Mpa/2.5
=48 Mpa
we know that,
V=P
<u>Area for shear head:</u>
A(head)=π×d×t
=π×0.04×0.075
=0.003×πm^2
<u>Area for plate:</u>
A(plate)=π×d×t
=π×0.08×0.03
=0.0024×πm^2
now we have to find shear stress for both head and plate
<u>For head:</u>
T_allow=V/A(head)
48 Mpa=P/0.003×π ..(V=P)
P =48 Mpa×0.003×π
=452.16 KN
<u>For plate:</u>
T_allow=V/A(plate)
48 Mpa=P/0.0024×π ..(V=P)
P =48 Mpa×0.0024×π
=361.91 KN
the boundary load is obtained as the minimum value of force P for all three cases. so the solution is
P=361.91 KN
note:
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