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1 answer:
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Answer:
Explanation:
Since we are given time, acceleration, and final velocity, we can use the following formula to find the initial velocity:
Our given values:
<em>Acceleration is negative because the car is slowing down.</em>
Add the values to the formula, and solve for :
Complete question:
The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The magnitude of the electric field between the plates is 100 kV/m. The plates each have an area of 2 x 10⁻³ m², and the spacing between the plates is 6 x 10⁻³ m. There is no dielectric between the plates. What is the charge on the capacitor?
Answer:
The charge on the capacitor is 1.77nC
Explanation:
Given;
magnitude of electric field between the plates, E = 100 kV/m
Area of each plate, A = 2 x 10⁻³ m²
Distance between the plates, d = 6 x 10⁻³ m
Charge on the capacitor is calculated as;
Q = CV
V = Ed
Therefore, the charge on the capacitor is 1.77nC