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Brums [2.3K]
3 years ago
10

The diameter of carbon atom is 0.000000000 154m. What is the number expressed in scientific notation

Chemistry
2 answers:
kogti [31]3 years ago
7 0
1.54×10 −10

one and fifty four-hundreths times ten to the power of negitiive 10
Drupady [299]3 years ago
7 0

Answer:

1.54 × 10⁻¹⁰ m

Explanation:

A number in scientific notation has the form A × 10ⁿ.

A is a number from 1 to 10, but not 10 itself and is called the <em>coefficient</em>.

n is an integer and is called the <em>exponent</em>.

To convert a small decimal number to exponential notation, you move the decimal point to the right until you have one nonzero digit in front of the decimal point.

The exponent is negative of the number of places you moved the decimal point.  

To convert 0.000 000 000 154 m to scientific notation:

  • Move the decimal point to the right until it is just past the 1. The coefficient is 1.54
  • Count the number of places you have moved the decimal (ten). The exponent is -10.

The number in scientific notation is 1.50 × 10⁻¹⁰.

Add the units and the <em>measurement</em> is 1.50 × 10⁻¹⁰ m.

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If a little old lady is doing 98.3 kilometers/hour, will she get a speeding ticket if the speed limit is 55 miles / hour? [USE:
shutvik [7]

Answer:

It is possible she could get one.

Explanation:

To solve this problem we need to convert 98.3 kilometers/hour to miles/hour.

In other words, we <u>convert km to mi</u>, to do so we multiply 98.3 km by a <em>conversion factor</em>, putting the unit we want to have in the numerator, and the unit we want to convert in the denominator:

  • 98.3 km * \frac{1000m}{1km} *\frac{100cm}{1m}*\frac{1in}{2.54cm} *\frac{1ft}{12in} *\frac{1mi}{5280ft} = 61 mi

Given that the little old lady is doing 61 miles/hour, she could get a speeding ticket.

7 0
3 years ago
Does anybody know how to do q4. Please show working out thanks.
insens350 [35]

Answer:

% purity of limestone = 96.53%

Explanation:

Question (4).

Weight of impure CaCO₃ = 25.9 g

Molecular weight of CaCO₃ = 40 + 12 + 3(16)

                                              = 100 g per mole

We know at S.T.P. number of moles of CO₂ = 1 and volume = 22.4 liters

From the given reaction, 1 mole of CaCO₃ reacts with 1 mole or 22.4 liters of

CO₂.

∵ 22.4 liters of CO₂ was produced from CaCO3 = 100 g

∴ 1 liter of CO₂ will be produced by CaCO₃ = \frac{100}{22.4}

∴ 5.6 liters of CO₂ will be produced by CaCO₃ = \frac{100\times 5.6}{22.4}

                                                                              = 25 g

Therefore, % purity of CaCO₃ = \frac{\text{Weight calculated}}{{\text{Weight given}}}\times 100

                                                 = \frac{25}{25.9}\times 100

                                                 = 96.53 %

7 0
3 years ago
In the uncatalyzed reaction N2O4 (g) ⇌ 2 NO2 (g) the pressure of the gases at equilibrium are PN2O4 = 0.377 atm and PNO2 = 1.56
larisa86 [58]

Answer:

The pressures will remain at the same value.

Explanation:

A catalyst is a substance that alter the rate of a chemical reaction. It either speeds up the or slows down the rate of a chemical reaction.

While a catalyst affects the rate, it is noteworthy that it has no effect on the equilibrium position of the chemical reaction. A catalyst works by creating an alternative pathway for the reaction to proceed. Most times, it decreases the activation energy needed to kickstart the chemical reaction.

Hence, we know that it has no effect on the equilibrium position. Factors affecting equilibrium position includes, temperature and concentration of reactants and products( pressure in terms of gases).

The reactants and the products here are gaseous, and as such pressure affects the equilibrium position. Now, we have established that the equilibrium position is unaffected. And as such the pressure affecting it does not change.

Thus, we have established that the pressure of the products and reactants are unaffected and as such they remain at their value unaffected.

8 0
3 years ago
Which products would form if chlorine gas was bubbled through a solution of sodium bromide
GaryK [48]
I honestly don’t know
3 0
2 years ago
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tresset_1 [31]
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Na2CO3 = 2Na+ + CO3^2-

7.15 g Na2CO3 - 10H2O (1 mol / 402.9319 g) (1 mol Na2CO3 / 1 mol Na2CO3 - 10H2O) ( 1 mol Na2CO3 / 1 mol Na2CO3-10H2O ) ( 2 mol Na+ / 1 mol Na2CO3) = 0.04 mol Na+ ions present
8 0
3 years ago
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