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Your answer is C. frequency
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Answer:
128 m
Explanation:
From the question given above, the following data were obtained:
Horizontal velocity (u) = 40 m/s
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Horizontal distance (s) =?
Next, we shall determine the time taken for the package to get to the ground.
This can be obtained as follow:
Height (h) = 50 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
50 = ½ × 9.8 × t²
50 = 4.9 × t²
Divide both side by 4.9
t² = 50 / 4.9
t² = 10.2
Take the square root of both side
t = √10.2
t = 3.2 s
Finally, we shall determine where the package lands by calculating the horizontal distance travelled by the package after being dropped from the plane. This can be obtained as follow:
Horizontal velocity (u) = 40 m/s
Time (t) = 3.2 s
Horizontal distance (s) =?
s = ut
s = 40 × 3.2
s = 128 m
Therefore, the package will land at 128 m relative to the plane
Answer: b. The flow of air is neither toward the warm air mass nor toward the cold air mass.
A stationary front forms between two air masses. A stationary front results when the warm front or cold front air stops moving. This occurs due to the fact that warm front and cold front air masses being opposite to each other but neither of them are able to repel the other. This affects the climatic conditions of the region. The weather is often cloudy along a stationary front and also supported with fall of rain and snow especially if the air in the front is cold with low atmospheric pressure.
<em>Therefore, along a stationary front the flow of air is neither toward the warm air mass nor toward the cold air mass.
</em>
Answer:
The kinetic energy of the arrow is equaled to the potential energy of the stretching of the bow, which in this case is 50 J.
Explanation:
Potential energy converts to kinetic as soon as it begins to move.
Answer:
The speed of the 8-ball is 2.125 m/s after the collision.
Explanation:
<u>Law Of Conservation Of Linear Momentum</u>
The total momentum of a system of masses is conserved unless an external force is applied. The momentum of a body with mass m and velocity v is calculated as follows:
P=mv
If we have a system of masses, then the total momentum is the sum of all the individual momentums:
When a collision occurs, the velocities change to v' and the final momentum is:
In a system of two masses, the law of conservation of linear momentum is simplified to:
The m1=0.16 Kg 8-ball is initially at rest v1=0. It is hit by an m2=0.17 Kg cue ball that was moving at v2=2 m/s.
After the collision, the cue ball comes to rest v2'=0. It's required to find the final speed v1' after the collision.
The above equation is solved for v1':
The speed of the 8-ball is 2.125 m/s after the collision.