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Licemer1 [7]
3 years ago
13

How many nonmetals are on the periodic table?

Chemistry
1 answer:
jekas [21]3 years ago
7 0
There are 17 nonmetals
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A 4.000 g sample of iron was heated from 0.0°C to 21.0°C. If it has a specific heat of 0.440 kJ/kg °C, how many kilojoules of he
Mashutka [201]
M = 4 g = 4/1000 kg = 0.004 kg, θ₂ = 21.0°C, θ₁ = 0°C , c = 0.44kJ/kg°C,

Q = mc(θ₂ - θ₁)

Q = 0.004*0.440*(21 - 0)

Q  =  0.03696 kJ 

0.03696 kJ<span> of heat is absorbed.</span>
6 0
3 years ago
What is the relationship between the atomic mass of a substance and its molar mass?
sdas [7]
The relationship is that atomic mass is used to calculate molar mass
Example: H2O
2(1.007) + 15.999
18.013
3 0
2 years ago
Provide an appropriate alkyne starting material A and intermediate product B. Omit byproducts. The number of carbon atoms in the
nadezda [96]

Answer:

C4H6 + 2HBr = C4H8Br2

Explanation:

Alkynes are organic molecules made of the functional group carbon-carbon triple bonds and are written in the empirical formula of CnH2n−2. They are unsaturated hydrocarbons.

Furthermore, Halogenation reaction of any alkyne such as but-2-yne with any of the hydro halogenated compounds such as HBr, HCl, HF or HI will give an alkane that will have the same number of carbon atoms in the starting material and in the final product.

Halogenation reaction is a reaction that occurs when one or more halogens are added to a substance. Halogens is the seventh column in the periodic table and it include fluorine, chlorine, bromine, iodine, and astatine.

6 0
3 years ago
An unknown element, X, has an atomic mass of 107.868 amu. The X-109 isotope (108.905 amu) is 48.16%. What is the amu of the othe
juin [17]

Answer:

106.905 amu is the mass of the other isotope

Explanation:

The atomic mass of an element is the sum of the masses of the isotopes multiplied by its abundance. The atomic mass of an element X with 2 isotopes is:

X = X-109*i + X-107*i

Where X is the atomic mass = 107.868 amu

X-109 = 108.905amu, i = 48.16% = 0.4816

X-107 = ?, i = 1-0.4816 = 0.5184

Replacing:

107.868amu = 108.905amu*0.4816 + X-107*0.5184

55.4194 = X-107*0.5184

106.905 = X-107

<h3>106.905 amu is the mass of the other isotope</h3>
4 0
3 years ago
3. Write a hypothesis that explains your inference about the acidity of the paper. How might you test your hypothesis by extendi
vredina [299]

Answer:

google

Explanation:

go to the plus thing on your screen and search it. (please dont attack me im doing a dare  >:( )

8 0
3 years ago
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