P = 43 * 10^3
V = 12 L
P' =?
V' = 8 L
PV = P'V'
43*10^3* 12 = P' * 8
I know you can do it from here, mate ;)
Answer:
304.9m
Explanation:
Given
Velocity = 300m/s
Tim = 1sec
Required
Horizontal distance S
Using the formula
S= ut+1/2gt²
S = 300(1)+1/2(9.8)(1)²
S = 300+4.9
S = 304.9m
Hence the distance travelled is 304.9m
The answer is 0.981 J
E = m · g · h<span>
E - energy
m - mass
g - gravitational acceleration
h - height
We know:
E = ?
m = 0.10 kg
g = 9.81 m/s</span>²
h = 1 m
E = 0.10 kg * 9.81 m/s² * 1 m = 0.981 J
Answer:
a) 
, b) 
, c) D. The magnitud of the change in the ball's momentum.
Explanation:
a) The magnitude of the change in the ball's momentum is:
![\Delta p = (0.275\,kg)\cdot \left[\left(1.63\,\frac{m}{s} \right)-\left(-3.28\,\frac{m}{s} \right)\right]](https://tex.z-dn.net/?f=%5CDelta%20p%20%3D%20%280.275%5C%2Ckg%29%5Ccdot%20%5Cleft%5B%5Cleft%281.63%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29-%5Cleft%28-3.28%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29%5Cright%5D)
b) The change in the magnitude of the ball's momentum:
![\Delta p' = (0.275\,kg)\cdot \left[(1.63\,\frac{m}{s} )-(3.28\,\frac{m}{s} ) \right]](https://tex.z-dn.net/?f=%5CDelta%20p%27%20%3D%20%280.275%5C%2Ckg%29%5Ccdot%20%5Cleft%5B%281.63%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29-%283.28%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%20%5Cright%5D)
c) The magnitude of the change in the ball's momentum is more directly related to the net force acting on the ball, as it measures the effect of the force on change in ball's motion at measured time according to the Impact Theorem. So, the right answer is option D.
Answer:
F= 403429 kpa
Explanation:
Pressure is the product of force and area
Mathematically,
P=F*A -------where F is force and A is area.
A= 40 *0.1 = 4mm² -----convert to m²
A= 4e⁻⁶ m²
P= 4000000 pa
F= P/A = 4000000/4e⁻⁶
F= 403428793.493 pa
F= 403429 kpa
