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xxMikexx [17]
3 years ago
7

Which type of flame(s) produce(s) incomplete combustion? Complete combustion?

Chemistry
1 answer:
Monica [59]3 years ago
8 0

Answer:

See the answer and explanation below, please.

Explanation:

There are 2 types of combustion:

-Complete: C02 (carbon dioxide) is generated and the flame is blue, in the presence of a large amount of oxygen.

-Incomplete: it is also generated as a product C0 (carbon monoxide) harmful to health, and the color of the flame is yellow. It is produced in the presence of a small amount of oxygen.

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Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2N
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Answer : The value of work done for the system is 1144.69 J

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\text{Moles of }NaN_3=\frac{20.2g}{65.01g/mole}=0.311mole

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2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 2 mole of NaN_3 react to give 3 mole of N_2

So, 0.311 moles of NaN_3 react to give \frac{0.311}{2}\times 3=0.466 moles of N_2

Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = ?

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R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 22^oC=273+22=295K

Putting values in above equation, we get:

1.00atm\times V=0.466mole\times (0.0821L.atm/mol.K)\times 295K

V=11.3L

As initially no nitrogen was present. So,

Volume expanded = Volume of nitrogen evolved

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Expansion work = Pressure × Volume

Expansion work = 1.00 atm × 11.3 L

Expansion work = 11.3 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 11.3 × 101.3 = 1144.69 J

Therefore, the value of work done for the system is 1144.69 J

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