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3 years ago

Which type of flame(s) produce(s) incomplete combustion? Complete combustion?

Chemistry

1 answer:

Monica [59]3 years ago

8 0

Answer:

See the answer and explanation below, please.

Explanation:

There are 2 types of combustion:

-Complete: C02 (carbon dioxide) is generated and the flame is blue, in the presence of a large amount of oxygen.

-Incomplete: it is also generated as a product C0 (carbon monoxide) harmful to health, and the color of the flame is yellow. It is produced in the presence of a small amount of oxygen.

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3 years ago

Bromine, a liquid at room temperature has a boiling point of 58 degrees celsius and a melting point at -7.2 degree celsius bromi

ra1l [238]

Hello!

Bromine can be classified as a pure substance.

Why?

Bromine is an element with atomic number 35 on group 17 of the Periodic Table. That's the first sign that shows us that it is a pure substance.

But the fact that it has a clear and defined boiling and melting point is a sign that we are in the presence of a pure substance. Pure substances are characterized by defined boiling and melting points.

Mixtures usually have a range of temperatures in which they melt and boil.

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4 years ago

A 52.0 g of Copper (specific heat=0.0923cal/gC) at 25.0C is warmed by the addition of 299 calories of energy. find the final tem

Leto [7]

Answer : The final temperature of the copper is, $87.29^oC$

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = heat gained = 299 cal

m = mass of copper = 52 g

c = specific heat of copper = $0.0923cal/g^oC$

$\Delta T=\text{Change in temperature}$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $25^oC$

Now put all the given values in the above formula, we get the final temperature of copper.

$299cal=52g\times 0.0923cal/g^oC\times (T_{final}-25^oC)$

$T_{final}=87.29^oC$

Therefore, the final temperature of the copper is, $87.29^oC$

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4 years ago

How many ways can you choose ten tadpoles from a pool of 20

Georgia [21]

Take half the amount

5 0

4 years ago

How many moles are there in 7.5 L Of H2

True [87]

So multiply number of moles x number of atoms/mole = 1.8066 x 10^24 atoms of H2. One mole of any gas at STP has a volume of 22.4 L. So first determine the number of moles of gas you have.
for example do 7
$7.5 \div 22.4$
that 's what I think

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3 years ago