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Fiesta28 [93]
3 years ago
11

How many moles of Hions are present in the following aqueous solution?

Chemistry
1 answer:
Fittoniya [83]3 years ago
6 0

Answer:

Nitric acid is a strong acid meaning it completely dissociates in water. Therefore, you can say that the concentration of H+ ions in solution is the same as the concentration of the acid (molar concentration). So once you have that, you can use the pH formula to find the pH of the acid.

pH = -log[H+]

So if you have .15 M HNO3 the pH is 0.82.

But, if you have a different concentration, the pH will change.

Explanation:

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Angelina_Jolie [31]
Answer is: there is 1,77·10²³ molecules of CH₂Cl₂.
m(CH₂Cl₂) = 25 g.
n(CH₂Cl₂) = m(CH₂Cl₂) ÷ M(CH₂Cl₂).
n(CH₂Cl₂) = 25 g ÷ 85 g/mol.
n(CH₂Cl₂) = 0,294 mol.
N(CH₂Cl₂) = n(CH₂Cl₂) · Na.
N(CH₂Cl₂) = 0,294 mol · 6,023 1/mol.
N(CH₂Cl₂) = 1,77·10²³.
n - amount of substance.
Na - Avogadro number.
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4 years ago
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Describe how you would prepare 350 ml of 0.100 m c12h22o11 starting with 3.00l of 1.50 m c12h22o11
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To prepare 350 mL of 0.100 M solution from a 1.50 M solution, we simply have to use the formula:

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So from the formula, we will know how much volume of the 1.50 M we actually need.

 

1.50 M * V1 = 0.100 M * 350 mL

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So we need 23.33 mL of the 1.50 M solution. We dilute it with water to a volume of 350 mL. So water needed is:

350 mL – 23.33 mL = 326.67 mL water

 

 

Steps:

1. Take 23.33 mL of 1.50 M solution

<span>2. Add 326.67 mL of water to make 350 mL of 0.100 M solution</span>

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3 years ago
Yvus UVILLE auuuulll
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