When an object is falling and reaches a constant velocity, the net force on the object is <em>zero</em> (it's not accelerating), and the weight of the object is equal to <em>the force of air resistance against the object</em>. (choice-D)
Answer:
False.
Explanation:
Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.
Answer:
C. The sum remains the same.
Explanation:
The sum of the kinetic and potential energy remains the same as the all rolls from point A to E.
We know this based on the law of conservation of energy that is in play within the system.
The law of conservation of energy states that "energy is neither created nor destroyed within a system but transformed from one form to another".
- At the top of the potential energy is maximum
- As the ball rolls down, the potential energy is converted to kinetic energy.
- Potential energy is due to the position of a body
- Kinetic energy is due to the the motion of the body
Answer:
it is below pls give 5 star
Explanation:
Foods contain stored potential energy in the form of chemical energy. When we consume food, the particles undergo a chemical reaction that releases the chemical energy. In turn, this energy is used by the body to perform its daily activities.
Therefore, when you eat a bowl of vegetable soup, you get the chemical energy that is stored in it.
RESULT
Foods contain stored potential energy in the form of chemical energy. When we consume food, the particles undergo a chemical reaction that releases the chemical energy. In turn, this energy is used by the body to perform its daily activities.
Therefore, when you eat a bowl of vegetable soup, you get the chemical energy that is stored in it
Answer:
8.136×10⁻⁵ J
Explanation:
Applying,
Q = Cv................ Equation 1
Where Q = Charge on the capacitor, v = voltage of the battery, C = capacitance of the capacitor.
From the question,
Given: C = 6.78μF = 6.78×10⁻⁶ F, v = 12 V
Substitute these values into equation 1
Q = (6.78×10⁻⁶ )(12)
Q = 8.136×10⁻⁵ J
Hence the charge on the capacitor is 8.136×10⁻⁵ J
