1/Rt=1/R1+1/R2+1/R3, 1/Rt=1/3+1/12+1/4=2/3, Rt=equivalent resistance= 1.5 ohms
Answer:
electric motors is the answer
Answer:
ExplanaThis is a way of measuring how much gravity there is. The formula is: weight/mass = gravitational field strength.
Gravitational field strength = Weight/mass unit is N/kg
Weight = mass x gravitational field strength unit is N
On Earth the gravitational field strength is 10 N/kg. Other planets have different gravitational field strengths. The Moon has a gravitational field strength of 1.6 N/kg. You might have seen films of astronauts leaping high on the moon.
Here on Earth, if I jump I am pulled back to ground by gravity. What is my weight? My mass is 80kg and if we multiply by gravitational field strength (10N/kg) - my weight is 800N. Now if I go to the moon, my mass will be the same, 80kg. We multiply that by the moon's gravitational field strength, which is 1.6 N/ kg. That means my weight on the moon is 128N. So I have different weights on the Earth and on the Moon. That's why astronauts can jump high into the air on the moon - they're lighter up there.
Jupiter is a very large planet with strong gravitational field strength of 25 N/ kg. My body is 80kg. If I go to Jupiter my weight is going to be 25 x 80 = 2,000 N. That means I wouldn't be able to get off the ground or stand up straight! I would probably be lying down all the time there. So weight varies depending on which planet you are on. You can find out more yourself by looking up tables of weight on different planets.tion:
pls brainlieste
To solve this problem it is necessary to apply the concepts related to the principle of superposition and the equations of destructive and constructive interference.
Constructive interference can be defined as
![dSin\theta = m\lambda](https://tex.z-dn.net/?f=dSin%5Ctheta%20%3D%20m%5Clambda)
Where
m= Any integer which represent the number of repetition of spectrum
= Wavelength
d = Distance between the slits.
= Angle between the difraccion paterns and the source of light
Re-arrange to find the distance between the slits we have,
![d = \frac{m\lambda}{sin\theta }](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7Bm%5Clambda%7D%7Bsin%5Ctheta%20%7D)
![d = \frac{2*536*10^{-9}}{sin(24)}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B2%2A536%2A10%5E%7B-9%7D%7D%7Bsin%2824%29%7D)
![d = 2.63*10^{-6}m](https://tex.z-dn.net/?f=d%20%3D%202.63%2A10%5E%7B-6%7Dm)
Therefore the number of lines per millimeter would be given as
![\frac{1}{d} = \frac{1}{2.63*10^{-6} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bd%7D%20%3D%20%5Cfrac%7B1%7D%7B2.63%2A10%5E%7B-6%7D%20%7D)
![\frac{1}{d} = 379418.5\frac{lines}{m}(\frac{10^{-3}m}{1 mm})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bd%7D%20%3D%20379418.5%5Cfrac%7Blines%7D%7Bm%7D%28%5Cfrac%7B10%5E%7B-3%7Dm%7D%7B1%20mm%7D%29)
![\frac{1}{d} = 379.4 lines/mm](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bd%7D%20%3D%20379.4%20lines%2Fmm)
Therefore the number of the lines from the grating to the center of the diffraction pattern are 380lines per mm
Answer:
Explanation:
Let the volume of the unknown bulb = X L
The volume of the system , after opening valve = (X + 0.72 L )
Use Boyles law gas equation,
P1V1 = P2V2 ( at temperature is constant )
Given:
P1 = 1.2 atm
P2 = 683 torr
Converting mmHg to atm,
1 atm = 760 mmHg(torr)
683 mmHg = 683/760
= 0.8987 atm
1.2X = 0.8987*(X + 0.720)
1.2X = 0.8987X + 0.6471
0.3013X = 0.6471
X = 2.15 L