Answer:
Reaction 1: Kc increases
Reaction 2: Kc decreases
Reaction 3: The is no change
Explanation:
Let us consider the following reactions:
Reaction 1: A ⇌ 2B ΔH° = 20.0 kJ/mol
Reaction 2: A + B ⇌ C ΔH° = −5.4 kJ/mol
Reaction 3: 2A⇌ B ΔH° = 0.0 kJ/mol
To predict what will happen when the temperature is raised we need to take into account Le Chatelier Principle: when a system at equilibrium suffers a perturbation, it will shift its equilibrium to counteract such perturbation. This means that <em>if the temperature is raised (perturbation), the system will react to lower the temperature.</em>
Reaction 1 is endothermic (ΔH° > 0). If the temperature is raised the system will favor the forward reaction to absorb heat and lower the temperature, thus increasing the value of Kc.
Reaction 2 is exothermic (ΔH° < 0). If the temperature is raised the system will favor the reverse reaction to absorb heat and lower the temperature, thus decreasing the value of Kc.
Reaction 3 is not endothermic nor exothermic (ΔH° = 0) so an increase in the temperature will have no effect on the equilibrium.
What’s wrong? ...........:.........
I think you meant K as in kilograms?
If so, the answer should be 0.0052.
Answer:
The name of the phase change is;
Sublimation.
Explanation:
CO₂(s) + energy ⇒ CO₂(g)
Sublimation is the transition of a substance from its solid state to the gaseous state without first turning to a liquid due the high rate of absorption of of thermal energy of the substance such that the substance does not melt first.
As such sublimation is the endothermic process taking place at a temperature and pressure lower than the triple point of the substance in the substance's phase diagram. The triple point is the lowest temperature and pressure at which a substance can exist as a liquid.
