2/5
0.4/1*10/10=4/10
4/10%2/2=2/5
To solve for the time an object takes to hit the ground, the equation
<em>y</em> <em>= y₀ + v₀t + ½gt²</em>, or just <em>0 = y₀ +½gt²</em> since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, <em>t = (−2y₀/g)^½.</em>
(-2*60/-9.8)^½ = 3.50 seconds.
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5x(4x^3 + 3x - 2)
There’s a 5 and a x common.
