Answer:
Periodic.
Explanation:
Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.
Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.
Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.
Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data.
Generally, a fixed speed is used for the propagation of traveling waves and this speed is usually denoted with the variable "v" or sometimes "c."
Furthermore, if the waveform of a traveling wave is repeated every time at specific intervals T, it is referred to as periodic wave.
Mathematically, the period of a traveling wave is given by the formula;
Where;
T is the time measured in seconds.
Answer:
Part a)
Part c)
This mean the truck is decelerating and its speed is decreasing
Part e)
Part f)
Explanation:
Part a)
Speed of the truck is given as
as we know that
1 km = 1000 m
1 h = 3600 s
so we will have
Part c)
Average acceleration is given as
now we have
Part e)
as we know that it is uniform acceleration
so we can say
Part f)
distance traveled by the truck is given as
Answer:
Explanation:
From the given information:
The car's initial velocity = 4 m/s in the direction of east 45° due north
We can therefore express the vector of this component form as:
v₁ = (4 m/s) (cos(45º)i + sin(45º)j)
v₁ = (2.83 m/s)i + (2.83 m/s)j
Similarly, the car's final velocity = 4 m/s in the direction of the east side 10º north
∴
v₂ = (4 m/s) (cos(10º) i + sin(10º) j)
v₂ = (3.94 m/s) i + (0.695 m/s) j
From the first equation of motion
v = u + at
Making acceleration "a" the subject of the formula, we have:
a = (v - u )/t
a = (v₂ - v₁)/t
a = (0.370 m/s²) + (-0.711 m/s²)
The magnitude of the avg. acceleration is:
And;
The direction can be determined by taking the tangent of the acceleration:
i.e.
Thus, the direction of the angle is approximately S 62.51º E
Explanation:
The 11Ω, 22Ω, and 33Ω resistors are in parallel. That combination is in series with the 4Ω and 10Ω resistors.
The net resistance is:
R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)
R = 20Ω
Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:
V = IR
120 V = I (20Ω)
I = 6 A
So the voltage drops are:
V = (4Ω) (6A) = 24 V
V = (10Ω) (6A) = 60 V
That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:
V = 120 V − 24 V − 60 V
V = 36 V
So the currents are:
I = 36 V / 11 Ω = 3.27 A
I = 36 V / 22 Ω = 1.64 A
I = 36 V / 33 Ω = 1.09 A
If we wanted to, we could also show this using Kirchhoff's laws.
