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Zanzabum
2 years ago
7

Who got the energy conversation in a system gizmo answers dm me on insta .al3xgonrockout​

Physics
1 answer:
Mars2501 [29]2 years ago
3 0

Answer:

a

Explanation:

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A person stands at the base of a hill that is a straight incline making an angle φ with the horizontal. For a given initial spee
Brums [2.3K]

Answer:

θ = sin⁻¹\sqrt{2gd}

Explanation:

From one of the equations of motion, v² = u² + 2as.......... equation 1

Since the object thrown was moving against gravity, then the acceleration, a would change to -g and the initial velocity u would change to V₀ sin θ because the object is travelling at angle of θ to the horizontal. By inputting all these parameter into equation 1, we would arrive at:

v² = (u sin θ)² - 2gd

(u sin θ)² = 2gd

d = (u sin θ)²/2g

sin² θ = 2gd

sin θ = \sqrt{2gd}

θ = sin⁻¹ \sqrt{2gd}

4 0
3 years ago
In a healthy body, the heart pumps blood efficiently. When the heart has a problem, heart failure can occur. Heart failure can h
cupoosta [38]

Answer:

the heart would fail to efficiently pump oxygenated blood to the body and lungs

3 0
3 years ago
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If you want to play a tune on wine glasses, you’ll need to adjust the oscillation frequencies by adding water to the glasses. Th
jonny [76]

Answer:Reducing mass i.e. water

Explanation:

Frequency For given mass in glass is given by

f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}

where k =stiffness of the glass

m=mass of water in glass

from the above expression we can see that if mass is inversely Proportional to frequency

thus reducing mass we can increase frequency  

6 0
3 years ago
A hot (70°C) lump of metal has a mass of 250 g and a specific heat of 0.25 cal/g⋅°C. John drops the metal into a 500-g calorimet
Gnom [1K]

Answer:

d. 37 °C

Explanation:

m_{m} = mass of lump of metal = 250 g

c_{m} = specific heat of lump of metal  = 0.25 cal/g°C

T_{mi} = Initial temperature of lump of metal = 70 °C

m_{w} = mass of water = 75 g

c_{w} = specific heat of water = 1 cal/g°C

T_{wi} = Initial temperature of water = 20 °C

m_{c} = mass of calorimeter  = 500 g

c_{c} = specific heat of calorimeter = 0.10 cal/g°C

T_{ci} = Initial temperature of calorimeter = 20 °C

T_{f} = Final equilibrium temperature

Using conservation of heat

Heat lost by lump of metal = heat gained by water + heat gained by calorimeter

m_{m} c_{m} (T_{mi} - T_{f}) = m_{w} c_{w} (T_{f} - T_{wi}) +  m_{c} c_{c} (T_{f} - T_{ci}) \\(250) (0.25) (70 - T_{f} ) = (75) (1) (T_{f} - 20) + (500) (0.10) (T_{f} - 20)\\T_{f} = 37 C

6 0
3 years ago
A 0.240 kg potato is tied to a string with length 1.90 m, and the other end of the string is tied to a rigid support. The potato
Luba_88 [7]

Explanation:

Below is an attachment containing the solution.

7 0
2 years ago
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