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IgorLugansk [536]
3 years ago
14

The net Forward force on the propeller of a 3.2 KG model airplane is 7.0 N. What is the acceleration of the airplanes

Physics
1 answer:
Alina [70]3 years ago
3 0

Answer:

2.1875 ms^{-2}

Explanation:

Newton's second law: F=ma Let's substitute and solve for whatever is left behind:7.0N= 3.2kg *a[tex]a =\frac {7.0}{3.2} \frac{N}{kg} = 2.1875 \frac{kg\frac{m}{s^2}}{kg}=2.1875 \frac{m}{s^2}

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