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3 years ago

The net Forward force on the propeller of a 3.2 KG model airplane is 7.0 N. What is the acceleration of the airplanes

Physics

1 answer:

Alina [70]3 years ago

3 0

Answer:

$2.1875 ms^{-2}$

Explanation:

Newton's second law: $F=ma$ Let's substitute and solve for whatever is left behind: $7.0N= 3.2kg *a[tex]a =\frac {7.0}{3.2} \frac{N}{kg} = 2.1875 \frac{kg\frac{m}{s^2}}{kg}=2.1875 \frac{m}{s^2}$

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