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3 years ago

A lady bug walks 10 cm forward then 5 cm backwards in 20 seconds. what is the average speed of the ladybug ?

Physics

2 answers:

lesantik [10]3 years ago

5 0

Answer:

The answer is average speed is equal to 0.25cm/sec

Step by step Explanation:

1-The average speed is defined as the relationship between the displacement that a body made and the total time it took to perform it.

2- The formula that allows to calculate the average velocity is $V = \frac{ΔX}{ΔT}$ where (V) is the average speed, (ΔX) is the displacement and (ΔT) is the time interval.

3- As the ladybug advanced 10cm and moved back 5cm we have that the displacement is equal to 5cm, and the time interval is equal to 20 sec.

4- having this we can replace the problem data and find the average speed.

$v = \frac{5cm}{20sec} \\v = 0.25\frac{cm}{sec}$

Kaylis [27]3 years ago

3 0

7.5 x 10^-3 ms^-1 OR 0.0075 m/s

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