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dybincka [34]
3 years ago
9

As defined by Aristotle, which one of the following is an element?

Chemistry
2 answers:
zloy xaker [14]3 years ago
8 0

Answer:

4

Explanation:

none of them

they are compounds and mixtures

Ksenya-84 [330]3 years ago
8 0

Answer:

4. none of them

Explanation:

Water is a compound.

Air is a mixture.

Soil is a mixture.

None of them are elements.

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How many moles are there in 13g of KMnO4?
Hoochie [10]

Answer:

0.08 moles

Explanation:

Relative atomic mass of KMnO4 = K + Mn + O4 = 39 + 55 + 16 x 4 = 158

=> Moles in 13g of KMnO4 = \frac{Mass}{Relative-atomic-mass} = \frac{13}{158} = 0.082278.. = 0.08 moles

3 0
3 years ago
Read 2 more answers
All atoms of the same element have the same what?
Paraphin [41]

Answer:

must have the same number of protons

8 0
3 years ago
Suppose the half-life of element k is 20 minutes. if you have a 200 g sample of k, how much of element k will be left after 60 m
vodka [1.7K]
T=20 min
m₀=200 g
t=60 min

the mass of element through time t is:
m=m₀*2^(-t/T)

m=200*2^(-60/20)=25 g

25 grams of element will be left after 60 minutes

5 0
3 years ago
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n unknown metal is either aluminum, iron or lead. If 150. g of this metal at 150.0 °C was placed in a calorimeter that contains
Nitella [24]

Answer : The metal used was iron (the specific heat capacity is 0.449J/g^oC).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of unknown metal = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of unknown metal = 150 g

m_2 = mass of water = 200 g

T_f = final temperature of water = 34.3^oC

T_1 = initial temperature of unknown metal = 150.0^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

150g\times c_1\times (34.3-150.0)^oC=-200g\times 4.184J/g^oC\times (34.3-25.0)^oC

c_1=0.449J/g^oC

Form the value of specific heat of unknown metal, we conclude that the metal used in this was iron (Fe).

Therefore, the metal used was iron (the specific heat capacity is 0.449J/g^oC).

6 0
4 years ago
A hollow conductor is positively charged. A small uncharged metal ball is lowered by a silk thread (insulating material) through
laiz [17]

Answer: Option (E) is the correct answer.

Explanation:

Since, the conductor is hollow which means that it is opened on both the ends. Hence, when a small uncharged metal ball is passed through it with the help of a silk thread then due to the presence of this insulating thread the ball will not come directly in contact with the charged rod.

As a result, there will occur no formation of opposite charge on the metal ball. Therefore, the ball will remain uncharged in nature.

Thus, we can conclude that after the given ball is removed, it will have no appreciable charge.

4 0
3 years ago
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