Answer:
the angular velocity of the car is 12.568 rad/s.
Explanation:
Given;
radius of the circular track, r = 0.3 m
number of revolutions per second made by the car, ω = 2 rev/s
The angular velocity of the car in radian per second is calculated as;
From the given data, we convert the angular velocity in revolution per second to radian per second.
Therefore, the angular velocity of the car is 12.568 rad/s.
If a surface looks "shiny" to you, that's because it reflects all
or most of the visible light that hits it. That doesn't always mean
that the same surface reflects other, non-visible wavelengths of
light. Infrared radiation may also reflect off of it, and probably
does. But you can't be sure just because it's visibly shiny.
Answer:
π/10 rads
Explanation:
It takes an hour (60 minutes) for the minute's hand to turn a full circle or achieve an angular rotation of
2πl rad.
Now, number of periods of 3 minutes in an hour is;
Number of periods = 60/3 = 20 periods
Thus, 3 minutes rotation accounts for 1/20 of 2π the rotation of the minute's hand in an hour.
Thus;
Angular displacement = (1/20) * 2π = π/10 rads
Answer:
ω = 1.83 rad/s clockwise
Explanation:
We are given:
I1 = 3.0kg.m2
ω1 = -5.4rad/s (clockwise being negative)
I2 = 1.3kg.m2
ω2 = 6.4rad/s (counterclockwise being positive)
By conservation of the momentum:
I1 * ω1 + I2 * ω2 = (I1 + I2) * ω
Solving for ω:
Since it is negative, the direction is clockwise.
Definitely ball and basket
