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DanielleElmas [232]
3 years ago
5

How does a quasar differ from a galaxy?

Physics
1 answer:
timama [110]3 years ago
5 0

A quasar is the center of a far distant galaxy, that has an extremely bright center. It's pretty much <span>an active galaxy.</span>


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A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.
GarryVolchara [31]

a) See free-body diagram in attachment

b) The book is stationary in the vertical direction

c) The net horizontal force is 35 N in the forward direction

d) The net force on the book is 35 N in the forward horizontal direction

e) The acceleration is 8.75 m/s^2 in the forward direction

Explanation:

a)

The free-body diagram of a body represents all the forces acting on the body using arrows, where the length of each arrow is proportional to the magnitude of the force and points in the same direction.

From the diagram of this book, we see there are 4 forces acting on the book:

- The applied force, F = 50 N, pushing forward in the horizontal direction

- The frictional force, F_f = 15 N, pulling backward in the horizontal direction (the frictional force always acts in the direction opposite to the motion)

- The weight of the book, W=mg, where m is the mass of the book and g=9.8 m/s^2 is the acceleration of gravity, acting downward. We can calculate its magnitude using the mass of the book, m = 4 kg:

W=(4)(9.8)=39.2 N

- The normal reaction exerted by the desk on the book, N, acting upward, and balancing the weight of the book

b)

The book is in equilibrium in the vertical direction, therefore there is no motion.

In fact, the magnitude of the normal reaction (N) exerted by the desk on the book is exactly equal to the weight of the book (W), so the equation of motion along the vertical direction is

N-W=ma

where a is the acceleration; however, since N = W, this becomes

a=0

And since the book is initially at rest on the desk, this means that there is no motion.

c)

We said there are two forces acting in the horizontal direction:

- The applied force, F = 50 N, forward

- The frictional force, F_f = 15 N, backward

Since they act along the same line, we can calculate their resultant as

\sum F = F - F_f = 50 - 15 = 35 N

and therefore the net force is 35 N in the forward direction.

d)

The net force is obtained as the resultant  of the net forces in the horizontal and vertical direction. However, we have:

- The net force in the horizontal direction is 35 N

- The net force in the vertical direction is zero, because the weight is balanced by the normal reaction

Therefore, this means that the total net force acting on the book is just the net force acting on the horizontal direction, so 35 N forward.

e)

The acceleration of the book can be calculated by using Newton's second law:

\sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

Here we have:

\sum F = 35 N (in the forward direction)

m = 4 kg

Therefore, the acceleration is

a=\frac{\sum F}{m}=\frac{35}{4}=8.75 m/s^2 (forward)

Learn more about forces, weight and Newton's second law:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

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#LearnwithBrainly

8 0
4 years ago
Let’s calculate Ms Jackson’s acceleration as she comes to a stop. Remember that the formula for acceleration is the change in ve
Natali [406]

Answer:

-1.5 m/s^2

Explanation:

The acceleration of an object is equal to the change in velocity of the object divided by the time taken for the object to change the velocity:

a=\frac{v-u}{t}

where:

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

For Ms Jackson in this problem, we have:

u = 6 m/s (initial velocity)

v = 0 m/s (final velocity)

t = 4 s (time elapsed)

Substituting into the equation, we find the acceleration:

a=\frac{0-6}{4}=-1.5 m/s^2

And the negative sign indicates that the direction of the acceleration is opposite to the direction of motion.

4 0
3 years ago
A ball is thrown straight up with a velocity of 16 m/s; what will be its velocity 2.0s after being released?
harkovskaia [24]
The answer for the question is 8m/s
4 0
3 years ago
A soccer ball is kicked at an angle of 30° to the horizontal with an initial velocity of 16 m/s. How high does the soccer ball g
OLEGan [10]
B.) should be the right/best answer if u divided 
6 0
4 years ago
what is the ratio of electrostatic force and the gravitational force between a proton and an electron?
Vadim26 [7]

Answer:

Explanation:

electron attraction between electron and nucleus = centripetal force of the orbiting electron

In fact, Bohr model depicts the atom as a nucleus surrounded by electrons in circular orbit around it, similar to the planets around the Sun. The centripetal force that keeps the electrons in circular motion around the nucles is provided by the electrostatic force between the electrons and the nucleus.

4 0
4 years ago
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