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3 years ago

What’s the answer? Will give brainliest

Physics

2 answers:

Feliz [49]3 years ago

7 0

Answer:

The correct answer is option d.

Explanation:

Fusion :It is defined as nuclear reaction in which two or more than two small nuclei combine together to form a large nucleus.

For example:

$^{2}_{1}H + ^{2}_{1}H \rightarrow ^{4}_{2}He$

Fission :It is defined as nuclear reaction in which a large nucleus of an atom splits into two or more than two small nuclei is known as a nuclear fission.

For example:

$^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He$ is a nuclear fission reaction.

The type of reaction shown in the figure demonstrates the process involved in nuclear fusion by binding together two nuclei.

Stella [2.4K]3 years ago

5 0

Answer:

The answer to your question is: letter D

Explanation:

Fussion: means combine 2 light nucleus to form heavier nucleus.

Fission: means splitting heavy nucleus to form lighter nucleus.

In the figure we can see two light nucleus that combine to form heavier nucleus, so the answer is nuclear fussion.

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Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.8×106N , one an angle 11degrees west of north an

sp2606 [1]

Answer: 2,9 ×10¹⁰J.

Explanation:

1. The work is a measure of energy and is calculated as the product of the displacement times the parallel force to such displacement.

That means that the only components of the force that contribute to work are those that result parallel to the displacement.

2. Since it is given that the two tugboats "pull the tanker a distance 0.83km toward the north", that is the displacement, and you have to calculate the net force toward the north.

3. Tugboat #1.

a) Force magnitude: F₁ = 1.8×10⁶N

b) Angle: α = 11° West of North

c) North component of the force F₁: Fy₁ = F₁cos(α) = 1.8×10⁶N × cos(11°) = 1.77×10⁶N

4. Tugboat #2:

a) Force magnitude: F₂ = 1.8×10⁶N

b) Angle: = 11° East of North

c) North component of the force F₂: Fy₂ = F₂cos(β) = 1.8×10⁶N × cos(11°) = 1.77×10⁶N =

5. Total net force, Fn:

Fn = Fy₁ + Fy₂ = 1.77×10⁶N + 1.77×10⁶N = 3.54×10⁶N

6. Work, W:

Displacement, d = 0.83 km = 8,300 m

W = Fn×d = 3.54×10⁶N×8,300m = 29,000 ×10⁶J = 2,9 ×10¹⁰J

The answer is rounded to two significant figures because both data, Force and displacement, have two significant figures.

7 0

3 years ago

A body weighing 108N moves with speed of 5m/s in a horizontal

poizon [28]

Answer:

i) 5 $m$ / $s^{2}$ ii) 54 $N$ iii) 54 $N$

Explanation:

i) $a = \frac{v^{2}}{r}$ ⇒ $a$ = 5² ÷ 5 = 5 $m/s^{2}$

ii) $m = \frac{W}{g}$ ⇒ $m$ = 108 ÷ 10 = 10.8 $kg$ , $F = ma$ ⇒ $F =$ 10.8 × 5 = 54 $N$

iii) F1 = F2 = 54 $N$

4 0

3 years ago

Under what conditions can an object have forces acting on it, but its motion does not change ?

Lady_Fox [76]

Answer: An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion.

Explanation: I hoped that helped!!

7 0

3 years ago

A river flows due south with a speed of 2.0 m/s. You steer a motorboat across the river; your velocity relative to the water is

neonofarm [45]

Answer:

a) 25.5°(south of east)

b) 119 s

c) 238 m

Explanation:

solution:

we have river speed $v_{r}$ =2 m/s