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postnew [5]
3 years ago
9

Which explains the downward force produced when air flows over the winglike spoiler on a race car?

Physics
1 answer:
professor190 [17]3 years ago
3 0
Newton's principle
newton's 2nd law of motion where F=ma
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What is the polarity of each of the earths magnetic poles ? Explain you answer
RideAnS [48]

Answer:

When you put un-like poles together (South facing North) you can feel magnetic attraction. In the Northern Hemisphere, your compass needle points North, but if you think about it for a moment, you will discover that the magnetic pole in the Earth's Northern Hemisphere has to be a South polarity.

3 0
3 years ago
Well-designed weight-training programs only target two or three body areas.<br> a. True<br> b. False
Sloan [31]
False<span>, well designed weight training programs actually target most of the muscles in the body. A good weight training program includes many compound exercises to activate multiple muscle groups and promote muscle hypertrophy. Some isolation exercises may also be included to target a specific muscle and help it grow.</span>
4 0
3 years ago
Read 2 more answers
A basketball player standing up with the hoop launches the ball straight up with an initial velocity of v_o = 3.75 m/s from 2.5
denis23 [38]

Answer:

a) The maximum height the ball will achieve above the launch point is 0.2 m.

b) The minimum velocity with which the ball must be launched is 4.43 m/s or 0.174 in/ms.

Explanation:

a)

For the height reached, we use 3rd equation of motion:

2gh = Vf² - Vo²

Here,

Vo = 3.75 m/s

Vf =  0m/s, since ball stops at the highest point

g = -9.8 m/s² (negative sign for upward motion)

h = maximum height reached by ball

therefore, eqn becomes:

2(-9.8m/s²)(h) = (0 m/s)² - (3.75 m/s²)²

<u>h = 0.2 m</u>

b)

To find out the initial speed to reach the hoop at height of 3.5 m, we again use 3rd eqn. of motion with h= 3.5 m - 2.5m = 1 m (taking launch point as reference), and Vo as unknown:

2(-9.8m/s²)(1 m) = (0 m/s)² - (Vo)²

(Vo)² = 19.6 m²/s²

Vo = √19.6 m²/s²

<u>Vo = 4.43 m/s</u>

Vo = (4.43 m/s)(1 s/1000 ms)(39.37 in/1 m)

<u>Vo = 0.174 in/ms</u>

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6 0
3 years ago
Across what potential difference does an electron have to be accelerated in order to reach the speed v=3e7 m/s?
zmey [24]

When an electron is accelerated through potential difference then the speed that it attain will be explained by energy conservation

here by energy conservation we can say that

change in kinetic energy of electron = electrostatic potential energy gained through given potential difference

kinetic energy is given as

KE = \frac{1}{2}mv^2

electrostatic potential energy is given as

PE = qV

now by energy conservation

qV = \frac{1}{2}mv^2

given that for electron

m = 9.1 * 10^{-31} kg

v = 3 * 10^7 m/s

q = 1.6 * 10^{-19} C

now by plug in values

1.6 * 10^{-19} * V = \frac{1}{2}*9.1* 10^{-31} *(3*10^7)^2

V = \frac{4.095 * 10^{-16}}{1.6 * 10^{-19}}

V = 2559.4 Volts

So here it is accelerated through potential difference of 2559.4 Volts

4 0
3 years ago
PLLLLLLLLLZ HELP 30 POINTS ANSWER ONLY IF YOU KNOW
Karo-lina-s [1.5K]

Answer:

  R^2 = 40^2 + 70^2 - 2(40)(70) cos 135°

Explanation:

The resultant connects the tail of the first vector to the head of the second vector (whose tail is at the head of the first vector). The three vectors form an obtuse triangle where the angle between the original direction and the second direction is 135°. The cosine factor in the Law of Cosines formula will be cos(135°), matching the second choice.

4 0
3 years ago
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