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3 years ago

Relate temperature to the average kinetic energy in a material.

Physics

1 answer:

inn [45]3 years ago

5 0

<u>Answer:</u>

Temperature is always directly proportional to average kinetic energy of the material.

<u>Explanation:</u>

The average kinetic energy is given by the formula

$\mathrm{K}=\frac{3}{2} \frac{R}{N A} T$

Where K = average kinetic energy . R = gas constant , NA = avogadro's number, T = temperature

From the formula we can clearly see that K is directly proportional to T i.e kinetic energy increases with increase in temperature.

As a substance when it absorbs the heat , temperature increases which makes the faster movement of the particles thus increasing the kinetic energy.The above formula is applicable to gaseous molecules.

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An object is spun around in circular motion such that its period is 0.2 seconds.

kherson [118]

Answer:

a. 5 Hertz

b. 35 rotations

Explanation:

a. Frequency is given by $f=\frac{1}{T}$ where $T$ is the period, in seconds. Given that $T=0.2$ , the frequency of this object's rotation is:

$f=\frac{1}{T}=\frac{1}{0.2}=\boxed{5\text{ Hz}}$

b. Since one rotation, or period, is completed in 0.2 seconds, divide the amount of time (7 seconds) by the time it takes to complete one revolution (0.2 seconds):

$\frac{7}{0.2}=\boxed{35 \text{ rotations}}$

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2 years ago

How would the weight of a 7-kilogram concrete block compared to the weight of a 7-kilogram metal sphere?

Hitman42 [59]

Answer:

C. The block and the sphere would have the same weight.

Explanation:

If both the block and the sphere weigh 7 kilograms then they have the same weight. They may look different, but they both weigh 7 kilograms.

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3 years ago

Read 2 more answers

Two long, straight wires are parallel and are separated by a distance of d = 0.210 m. The top wire in the sketch carries current

love history [14]

Answer:

$1.88\cdot 10^{-5} T$ , inside the plane

Explanation:

We need to calculate the magnitude and direction of the magnetic field produced by each wire first, using the formula

$B=\frac{\mu_0 I}{2\pi r}$

where

$\mu_0$ is the vacuum permeability

I is the current

r is the distance from the wire

For the top wire,

I = 4.00 A

r = d/2 = 0.105 m (since we are evaluating the field half-way between the two wires)

$B_1 = \frac{(4\pi\cdot 10^{-7})(4.00)}{2\pi(0.105)}=7.6\cdot 10^{-6}T$

And using the right-hand rule (thumb in the same direction as the current (to the right), other fingers wrapped around the thumb indicating the direction of the magnetic field lines), we find that the direction of the field lines at point P is inside the plane

For the bottom wire,

I = 5.90 A

r = 0.105 m

$B_2 = \frac{(4\pi\cdot 10^{-7})(5.90)}{2\pi(0.105)}=1.12\cdot 10^{-5}T$

And using the right-hand rule (thumb in the same direction as the current (to the left), other fingers wrapped around the thumb indicating the direction of the magnetic field lines), we find that the direction of the field lines at point P is also inside the plane

So both field add together at point P, and the magnitude of the resultant field is:

$B=B_1+B_2 = 7.6\cdot 10^{-6} T+1.12\cdot 10^{-5}T=1.88\cdot 10^{-5} T$