Ti + 2 Cl2 → TiCl4
(3.00 g Ti) / (47.867 g Ti/mol) = 0.062674 mol Ti
(6.00 g Cl2) / (70.9064 g Cl2/mol) = 0.084619 mol Cl2
0.084619 mole of Cl2 would react completely with 0.084619 x (1/2) = 0.0423095 mole of Ti, but there is more Ti present than that, so Ti is in excess and Cl2 is the limiting reactant.
(0.084619 mol Cl2) x (1 mol TiCl4 / 2 mol Cl2) x (189.679 g TiCl4/mol) = 8.025 g TiCl4 in theory
(7.7 g) / (8.025 g) = 0.96 = 96% yield TiCl4
Answer:
woodpecker it's easy lil lol
Answer:
The electrons where in motion
Answer:
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Explanation:
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<u>Answer:</u> The Henry's law constant for oxygen gas in water is 
<u>Explanation:</u>
To calculate the molar solubility, we use the equation given by Henry's law, which is:

where,
= Henry's constant = ?
= solubility of oxygen gas = 
= partial pressure of oxygen gas = 2.1 atm
Putting values in above equation, we get:

Hence, the Henry's law constant for oxygen gas in water is 