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Answer:
a) 7.0.
b) Nickel sulfate hepta hydrate.
c) 280.83 g/mol.
d) 44.9%.
Explanation:
<u><em>a) What is the formula of the hydrate?</em></u>
The mass of the hydrated sample (NiSO₄.xH₂O) = 5.0 g,
The mass of the anhydrous salt (NiSO₄) = 2.755 g,
The mass of water = 5.0 g - 2.755 g = 2.245 g.
∴ no. of moles of water = mass/molar mass = (2.245 g)/(18.0 g/mol) = 0.1247 mol.
∴ no. of moles of anhydrous salt (NiSO₄) = mass/molar mass = (2.755 g)/(154.75 g/mol) = 0.0178 mol.
∴ water of crystallization in the sample (x) = no. of moles of water/no. of moles of anhydrous salt (NiSO₄) = (0.1247 mol)/(0.0178 mol) = 7.0.
<u><em>b) What is the full chemical name for the hydrate?</em></u>
The name of the salt (NiSO₄.7H₂O) is Nickel sulfate hepta hydrate.
<u><em>c) What is the molar mass of the hydrate? </em></u>
(NiSO₄.7H₂O)
The molar mass = molar mass of NiSO₄ + 7(molar mass of H₂O) = (154.75 g/mol) + 7(18.0 g/mol) = 280.83 g/mol.
<em><u>d) What is the mass % of water in the hydrate?</u></em>
The mass % of water = (mass of water)/(mass of hydrated sample) x 100 = (2.245 g)/(5.0 g) x 100 = 44.9%.
Answer:
D. 77.0%
Explanation:
% yield = actual yield/theoretical yield x 100%
% yield = 1.57 g / 2.04 g x 100%
% yield = 76.96 (round up)
Answer:
4 biological membranes.
Explanation:
So in total, your water molecule has to go through your cell membrane, reach the outer membrane of your chloroplast and then through the inner membrane, and then lastly, it has to go through your thylakoid membrane to reach its final destination of the illumine. So in total 4 biological membranes.
Answer:
Certain types of atoms are "radioactive," meaning that they will eventually decay, or "break down" into a different type of atom. In this activity, you will simulate radioactive decay by flipping coins. Coins that land tails-up "decay," and coins that land heads-up remain the same.
Explanation:
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