A current of 0. 82A flows through a light bulb. The charge passed through the light bulb during 94 s is 77.08C
The amount of charge flown for a given period of time determines the current passed through a bulb or electrical body.
The relation between the charge, current and time is given as:
Q = I × t
where, Q is the charge flown through bulb
I is the current passed through bulb
t is the time for which charge passes through bulb
Given,
I = 0.82A
t = 94s
Q = ?
Substituting the values in the above formula:
Q = I × t
Q = 0.82 × 94
Q = 77.08C
Hence, The charge passed through the light bulb during 94 s is 77.08C
Learn more about Current here, brainly.com/question/2264542
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Answer:
I'm just going to tell you the information you need but not the answer so you can learn from the problem.
Explanation:
So he was at 248 km mark and traveled 99 km to get to the 149km mark. Then he turns around to go back 18 km to the 167 km mark. That is all the information you need to complete the question I recommend drawing it out in your notes.
Answer:
0.175 m/s²
Explanation:
Given:
v₀ = 35 m/s
v = 42 m/s
t = 40 s
Find: a
v = at + v₀
42 m/s = a (40 s) + 35 m/s
a = 0.175 m/s²
Answer:
<h2>35</h2>
Explanation:
According to snell's law which states that the ratio of the sin of incidence (i) to the angle of refraction(n) is a constant for a given pair of media.
sini/sinr = n
n is the constant = refractive index
Since the diver shines light up to the surface of a flat glass-bottomed boat, the refractive index n = nw/ng
nw is the refractive index of water and ng is that of glass
sini/sinr = nw/ng
given i = 30°, nw = 1.33, ng = 1.5, r = angle the light leave the glass
On substitution;
sin 30/sinr = 1.33/1.5
1.5sin30 = 1.33sinr
sinr = 1.5sin30/1.33
sinr = 0.75/1.33
sinr = 0.5639
r = arcsin0.5639
r ≈35°
angle the light leave the glass is 35°
