To solve this problem it is necessary to apply the concepts related to Normal Force, frictional force, kinematic equations of motion and Newton's second law.
From the kinematic equations of motion we know that the relationship of acceleration, velocity and distance is given by

Where,
Final velocity
Initial Velocity
a = Acceleration
x = Displacement
Acceleration can be expressed in terms of the drag coefficient by means of
Frictional Force
Force by Newton's second Law
Where,
m = mass
a= acceleration
Kinetic frictional coefficient
g = Gravity
Equating both equation we have that



Therefore,


Re-arrange to find x,

The distance traveled by the car depends on the coefficient of kinetic friction, acceleration due to gravity and initial velocity, therefore the three cars will stop at the same distance.
Answer:
756.88 Volts will be the potential difference across each capacitor.
Explanation:

Q = Charge on capacitor
C = Capacitance
V = Voltage across capacitor
Capacitance of first capacitor = 
Charge of first capacitor = 
Voltage across first capacitor = 


Capacitance of first capacitor = 
Charge of second capacitor = 
Voltage across first capacitor = 


Both the capacitors are disconnected and positive plates are now connected to each other and the negative plates are connected to each other. These capacitors are connected in parallel combination.
Total charge = Q

Total capacitance in parallel combination:

Potential across both capacitors = V

756.88 Volts will be the potential difference across each capacitor.
Sir Isaac Newton concluded that two factors—inertia and gravity–combine to keep Earth in orbit around the sun, and the moon in orbit around Earth. Hope this helps!
Answer:
2000 ohms
Explanation:
Resisters in series just add.
Rt = R1 + R2 + R3
R1 = 650 ohm
R2 = 350 ohm
R3 = 1000 ohm
Rt = 650 + 350 + 1000
Rt = 2000 ohms.
Answer:
The transverse displacement is
Explanation:
From the question we are told that
The generally equation for the mechanical wave is

The speed of the transverse wave is 
The amplitude of the transverse wave is 
The wavelength of the transverse wave is 
At t= 0.150s , x = 1.51 m
The angular frequency of the wave is mathematically represented as

Substituting values


The propagation constant k is mathematically represented as

Substituting values


Substituting values into the equation for mechanical waves
