Whatever phase of the moon Ike sees, he can expect to see
the same phase of moon again, after 29.53 days later.
Well, im pretty sure that when we do touch eachother, the atoms themselves are touching. idk if this is what ur looking for but hope this helps.
It's hard to tell exactly what's happening in that 110 cm that you marked over the wave. What is under the ends of the long arrow ? How many complete waves ? I counted 4.5 complete waves ... maybe ?
If there are 4.5 complete waves in 110cm, then the length of 1 wave is (110/4.5)=24.44cm.
Frequency = speed/wavelength
Frequency = 2m/s /0.2444m
Frequency = 8.18 Hz
Answer:
17.565 kgm/s
Explanation:
Momentum = mass × velocity
I = mv..................... Equation 1
But we can calculate the value of v using the equation of motion under gravity.
v² = u²+2gs............. Equation 2
Where u = initial velocity, s = maximum heigth, g = acceleration due to gravity.
Given: u = 0 m/s (at the maximum heigth), s = 7.0 m.
Constant: g = 9.8 m/s²
Substitute these values into equation 2
v² = 0²+ 2×7×9.8
v² = 137.2
v = √137.2
v = 11.71 m/s.
Also given: m = 1.50 kg
substitute these values into equation 1
Therefore,
I = 1.5×11.71
I = 17.565 kgm/s
Answer:
10mm
Explanation:
According to Hooke's law which states that "the extension of an elastic material is directly proportional to the applied force provided the elastic limit is not exceeded. Direct proportionality there means, increase/decrease in the force leads to increase/decrease in extension.
Mathematically, F = ke where;
F is the applied force
k is the elastic constant
e is the extension
from the formula k = F/e
k = F1/e1 = F2/e2
Given force of 1N indents the spring inwards by 2mm, this means force of 1N generates extension of 2mm
Let F1 = 1N e1 = 2mm
The extension that will be produced If force of 5N is applied to the string is what we are looking for. Therefore F2 = 5N; e2= ?
Substituting this values in the formula above we have
1/2=5/e2
Cross multiplying;
e2 = 10mm
This shows that we must have dent it by 10mm before it pushes outwards by a 5N force
