Several short trips taken from a cold start can use ...twice... as much fuel as a longer multi-purpose trip covering the same distance when the engine is warm.
In cold weather, properly designed gasoline aids in engine starting, while in hot weather, it helps prevent vapor lock. In order to meet the requirements of a modern engine, the fuel must have the volatility for which the engine's fuel system was built and an antiknock quality strong enough to prevent knock during routine operation.
During the intake phase, the air and fuel are combined before being introduced into the cylinder. The spark ignites the fuel-air mixture after the piston compresses it, resulting in combustion. During the power stroke, the piston is propelled by the expansion of the combustion gases.
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Answer: momentum has the same direction as that of velocity but when 2 bodies with the same linear momentum & different velocities it has different masses because a vector quantity is represented by a cross product of mass and velocity of object .
Answer:
the wagon should be used as frame of reference if an observer said the child was not moving.
Explanation:
The state of motion of a body depends upon the frame of reference. It is the set of co-ordinates according to which the motion is analyzed. If a child is riding in a wagon, then he will be considered in motion to a person standing outside the wagon. Hence, if we take a frame of reference outside the wagon then the child must be in motion with respect to the observer. On the other hand if the observer is inside the wagon, then the child must be in rest with respect to the observer. Hence, if we take the wagon to be the frame of reference, then the child will be at rest with respect to the observer.
<u>Therefore, the wagon should be used as frame of reference if an observer said the child was not moving.</u>
Answer:
-2.85 * 10^(-17) J
Explanation:
Parameters given:
Final velocity, v = 9 * 10^6 m/s
Initial velocity, u = 4.5 * 10^6 m/s
Using the conservation of energy formula, total energy is conserved:
K.Ein + PEin = KEf + PEf
K.Ef - K.Ein = P.Ein - P.Ef
=> -∆P.E = K.Ef - K.Ein
∆P.E = K.Ein - K.Ef
∆P.E = ½mu² - ½mv²
∆P.E = ½m[(4.5 * 10^6)² - (9 * 10^6)²]
∆P.E = ½ * 9.31 * 10^(-31) * (-61.25 * 10¹²)
∆P.E = -2.85 * 10^(-17) J
When the culture is discontinued from the bla bla bla
