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DaniilM [7]
3 years ago
10

What describes the relationship between the frequency, wavelength, and speed of a wave as the wave travels through different med

ia
Physics
1 answer:
zubka84 [21]3 years ago
7 0

speed \: of \: wave \:  = wavelength \times frequency
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which of the following statements is a reasonable conclusion about the Arctic ecosystem? a)The number of offspring produced is a
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Answer:

A is the answer

Explanation:

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3 years ago
A car is traveling at a constant speed of 20 m/s for 3 seconds. Then the driver puts on the brakes. The total distance the car t
yarga [219]

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15 seconds

Explanation:

If car was moving at 20m/s for 3 sec.

if car traveled 100m = 15 sec total

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A 61.0-kg person jumps from rest off a 10.0-m-high tower straight down into the water. Neglect air resistance. She comes to rest
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Answer:

Explanation:

In this case, law of conservation of energy will be implemented. It states that "the energy of the system remains conserved until or unless some external force act on it. Energy of the system may went through the conversion process like kinetic energy into potential and potential into kinetic energy.But their total always remain the same in conserved systems."

Given data:

Height of tower = 10.0 m

Depth of the pool = 3.00 cm

Mass of person = 61.0 kg

Solution:

Initial energy = Final energy

U_{i} =  (K.E) + U_{f}

As the person was at height initially so it has the potential energy only.

mg(h_{1} +h_{2}) = K.E + mgh_{2}

K.E = mgh_{1}

K.E = (61.0)(9.8)(10)\\K.E = 5978 J

Lets find out the magnitude of the force that the water is exerting on the diver.

W =ΔK.E

F.h_{2} = 5978\\

F = \frac{5978}{3}

F = 1992.67 N

7 0
3 years ago
Which has greater kinetic energy, a car traveling at 30 km/hr or a car of half the mass traveling at 60 km/hr?
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Half mass car because it's traveling faster

5 0
3 years ago
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A satellite revolves around a planet at an altitude equal to the radius of the planet. the force of gravitational interaction be
padilas [110]
Let
M = the mass of the planet
n = the mass of the satellite.
r = the radius of the planet

When the satellite is at a distance r from the surface of the planet, the distance between the centers of the two masses is 2r.
The gravitational force between them is
f_{0} = \frac{GMm}{(2r)^{2}} = \frac{1}{4} ( \frac{GMm}{r^{2}} )
where
G =  the gravitational constant.

When the satellite is on the surface of the planet, the distance between the two masses is r.
The gravitational force between them is
f_{4} =   \frac{GMm}{r^{2}} =4f_{0}

Answer:  f_{4} = 4f_{0}

5 0
4 years ago
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