What describes the relationship between the frequency, wavelength, and speed of a wave as the wave travels through different med

Suppose Car 1 collides with Car 2; Car 2 was not moving. In an ideal situation with no friction, according to the Law of Conserv

insens350 [35]

Your answer is C it is slightly reduced

4 0

3 years ago

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Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write

fomenos

Answer:

(a) $\vec{R}= 4.83\ m\ \hat{i}+1.47\ m\ \hat{j}$

(b) (5.05 m, 16.93 degrees wrt x-axis)

Explanation:

Given:

$\vec{D}$ = (3.00 m, 315 degrees wrt x-axis)
$\vec{E}$ = (4.50 m, 53.0 degrees wrt x-axis)

Let us first fond out vector D and E in their rectangular form.

$\vec{D} = (3\cos 315^\circ\ \hat{i}+3\sin 315^\circ\ \hat{j})\ m\\\Rightarrow \vec{D} = (2.12\ \hat{i}-2.12\ \hat{j})\ m\\$

Similarly,

$\vec{E} = (4.5\cos 53^\circ\ \hat{i}+4.5\sin 53^\circ\ \hat{j})\ m\\\Rightarrow \vec{D} = (2.71\ \hat{i}+3.59\ \hat{j})\ m\\\because \vec{R}=\vec{D}+\vec{E}\\\therefore \vec{R} = (2.12\ \hat{i}-2.12\ \hat{j})\ m+(2.71\ \hat{i}+3.59\ \hat{j})\ m\\\Rightarrow \vec{R} = (4.83\ \hat{i}+1.47\ \hat{j})\ m$

Part (a):

We can write the resultant vector R as below:

$\vec{R} = (4.83\ \hat{i}+1.47\ \hat{j})\ m$

Part (b):

$Magnitude\ of\ resultant = \sqrt{4.83^2+1.47^2}\ m = 5.05\ m\\\textrm{Direction in angle with the x-axis} = \theta = \tan^{-1}(\dfrac{1.47}{4.83})= 16.93^\circ$

Since both the components of the resultant lie on the positive x and y axes. So, the resultant makes an acute angle with the positive x-axis.

So, R = (5.05 m, 16.93 degrees wrt x-axis)

3 0

2 years ago

A light ray is incident on a reflecting surface. If the light ray makes a 40° angle with respect to the normal to the surface, w

mash [69]

Answer:

40°

Explanation:

when a ray light is incident on a surface it makes a 40° angle with the normal to the surface (reflecting surface ). this called angle of incidence.

And the angle made by reflected ray with the normal to the surface is called angle of reflection.

by the law of reflection angle of incidence is equal to the angle of reflection

hence the answer to the question is 40° ( because ∠i =∠r )

7 0

3 years ago

A particle with kinetic energy equal to 282 J has a momentum of magnitude 26.4 kg · m/s. Calculate the speed (in m/s) and the ma

masha68 [24]

Answer:

$v=21.36\,\,\frac{m}{s}\\$

$m=1.2357\,\,kg$

Explanation:

Recall the formula for linear momentum (p):

$p = m\,v$ which in our case equals 26.4 kg m/s

and notice that the kinetic energy can be written in terms of the linear momentum (p) as shown below:

$K=\frac{1}{2} m\,v^2=\frac{1}{2} \frac{m^2\,v^2}{m} =\frac{1}{2}\frac{(m\,v)^2}{m} =\frac{p^2}{2\,m}$

Then, we can solve for the mass (m) given the information we have on the kinetic energy and momentum of the particle:

$K=\frac{p^2}{2\,m}\\282=\frac{26.4^2}{2\,m}\\m=\frac{26.4^2}{2\,(282)}\,kg\\m=1.2357\,\,kg$

Now by knowing the particle's mass, we use the momentum formula to find its speed:

$p=m\,v\\26.4=1.2357\,v\\v=\frac{26.4}{1.2357} \,\frac{m}{s} \\v=21.36\,\,\frac{m}{s}$

4 0

2 years ago

A 1-kg ball is thrown at 10 m/s straight upward. neglecting air resistance, the net force that acts on the ball when it is half

Marrrta [24]

Because of gravity it has 10N force downward

4 0

3 years ago

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