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Lera25 [3.4K]
2 years ago
8

What is defined as anything made up of atoms that has mass and takes up space?

Physics
2 answers:
MrMuchimi2 years ago
3 0

The answer is matter.


Ulleksa [173]2 years ago
3 0

Answer:

matter

Explanation:

I took the test  

You can see other question and answer in my article.  

Just search in search engine with: Learningandassignments diy4pro  

Click on my site and find these related article post:  

Atoms Quiz- Grade 8 Unit 2 Leson 2

Hope it helps.  

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Why can’t a real machine ever have 100% efficiency
Harman [31]

Answer:

Almost all machines require energy to offset the effects of gravity, friction, and air/wind resistance. Thus, no machine can continually operate at 100 percent efficiency.

4 0
3 years ago
please help me with my question I will like and mark as brainliest NO LINKS THEY DON'T WORK AND IF U DON'T KNOW THE ANSWER PLS D
bearhunter [10]

Answer:

a)

Weight in Air = 0.3N

Weight in Water = 0.25N

Weight in Liquid = 0.24N.

Upthrust /Buoyant Force = Weight in Air – Weight in Fluid(Water in this case)

= 0.3 – 0.25

= 0.5N.

b) R.D of Body = Density of Body/Density of Standard Fluid(Water).

There's a Derived Formula for RD.

I'm gonna Apply it here.

Ask me for the derivation in the Comment section if you need it.

RD = α/ρ = (Weight in Air) / (Upthrust Force)

Where

α = density of the Body(or reference substance)

ρ = density of standard fluid (water)

= 0.3/0.05 = 6.

c) RD of Liquid = (Density of Liquid) /(Density of standard Fluid(water)

Or we just go by that formula

RD of Liquid = Weight in Air/Upthrust(In Liquid)

We'll be using the Upthrust in that Liquid now.

= 0.3 – 0.24 = 0.06

RD = 0.3/0.06 = 5.

7 0
2 years ago
How do waves behave differently to Earth's interior as they encounter the boundaries of different mediums?
Natalka [10]

Answer:

Explanation:

When they encounter boundaries between different media, the waves react according to Snell’s law, and the angle of refraction across the boundary will depend on the velocity of the second media relative to the first

3 0
2 years ago
Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molec
Vlad1618 [11]

Complete Question

Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molecules at T=27C temperature if corresponding resonant infrared frequencies (equivalent to frequencies of nuclei vibrations) of CCl4 molecule are 217, 315, 457 and 774 cm-1 . (Note: Wavenumber N in cm-1 is defined as N=1/\lambda\  cm^{-1})

Answer:

The ratio of intensities is  I_1 : I_2 : I_3 : I_4 = 217 : 315 : 457 : 774

Explanation:

 From the question we are told that

        The number of sets of satellite is n = 4

        The temperature is  T = 27 ^oC

        The resonant infrared frequencies are f_1 = 217 cm^{-1}

                                                                          f_2 = 315 cm^{-1}

                                                                          f_3 = 457 cm^{-1}

                                                                          f_4 = 774 cm^{-1}

From the question we see that the wave number also has a unit ofcm^{-1} hence  the value of the wave numbers of the molecule are

                                                                            N_1 = 217 cm^{-1}                

                                                                          N_2 = 315 cm^{-1}

                                                                          N_3 = 457 cm^{-1}

                                                                          N_4 = 774 cm^{-1}

Generally intensity is mathematically represented as

             I = \frac{nhc}{A \lambda }

Here we see that  I varies inversely with wavelength  i,.e

         I \ \ \alpha \ \ \frac{1}{\lambda }              

From the question we are told that the wave number is mathematically represented as

         N  = \frac{1}{\lambda }

Therefore

          I \ \ \alpha \ \  N

This implies that  the ratio of intensity in first set to that of second set to that of third set to that of fourth set is  equal to the ratio of the wavenumber in the first set to that of the second set  to that of third set to that of fourth

     This is mathematically represented as

               I_1 : I_2 : I_3 : I_4 = N_1 : N_2 : N_3 : N_4

Substituting values

        I_1 : I_2 : I_3 : I_4 = 217 : 315 : 457 : 774

                     

5 0
3 years ago
A student starts a stop-watch when the bob reaches to point M.He counts each time the bob changes direction and stop the watch o
azamat

Answer:

m

Explanation:

.

3 0
2 years ago
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