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photoshop1234 [79]
4 years ago
11

At the bottom of the ocean, a rock has a mass 25 g. At sea level, the same rock will have a mass of: less than 25 g, more than 2

5 g, or the same as 25 g?
Physics
2 answers:
storchak [24]4 years ago
5 0
It will be same 25 g
ivann1987 [24]4 years ago
5 0

Answer:

Option (2)

Explanation:

The weight of an object is always more at the sea level than at the base of the ocean floor. The water always forces an upward thrust to an object, as a result of which the weight of the object gets reduced by a certain amount. This property of water generating an upward force is known as the the buoyancy.

Thus, if an object weighs 25 grams at the ocean floor, then at the mean sea level, the weight is slightly more than 25 grams.

Hence, the correct answer is option (2).

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Muscular strength allows you to?
notka56 [123]

Answer:

Carry out daily activities

Explanation:

lift heavy objects,

walk,

look fit for the ladies.

5 0
2 years ago
Read 2 more answers
A 11.0 kg satellite has a circular orbit with a period of 1.80 h and a radius of 7.50 × 106 m around a planet of unknown mass. I
Anuta_ua [19.1K]

Answer:

Explanation:

Expression for times period of a satellite can be given as follows

Time period T = 1.8 x 60 x 60

= 6480

T² = \frac{4\times \pi^2\times r^3}{GM} where T is time period , r is radius of orbit , G is gravitational constant and M is mass of the satellite.

6480² = 4 x 3.14² x 7.5³ x 10¹⁸ / GM

GM = 4 x 3.14² x 7.5³ x 10¹⁸ / 6480²

= 3.96 X 10¹⁴

Expression for acceleration due to gravity

g = GM / R² where R is radius of satellite

20 = 3.96 X 10¹⁴ / R²

R² = 3.96 X 10¹⁴ / 20

= 1.98 x 10¹³ m

R= 4.45 x 10⁶ m

8 0
3 years ago
Is it possible to produce a continuous and oriented aramid fiber–epoxy matrix composite having longitudinal and transverse modul
gregori [183]

Answer:

It is not possible to produce continued and oriented fiber.

Explanation:

To solve the problem it is necessary to take into account the concepts related to Fiber volume ratio. The amount of fiber in a fiber reinforced compound corresponds directly to the mechanical properties of the compound. Given the fiber volume fraction, the theoretical elastic properties of a compound can be determined. The elastic modulus of a compound in the fiber direction of a unidirectional compound can be calculated using the following equation:

E = (1-V_f)E_m+V_fE_f

Where,

E is the longitudinal modulus of Elasticity

V_f is the fiber volume ratio

E_m is the elastic modulus of the matrix

E_f is the elastic modulus of the fibers

We need to consult the table of characteristics of Fibers and Reinforcements of Materials, in which they specify that the modulus of elasticity of the aramid fiber-epoxy is

E_f = 131Gpa

Moreover from the statement,

E = 35Gpa

E_m = 3.4Gpa

Replacing in the previous equation,

35 = 3.4 (1-V_f)+131V_f

V_f = 0.25 \rightarrow longitudinal

To make the comparison we now calculate the Fiber volume ratio through the transverse elastic modulus,

E = \frac{E_mE_f}{(1-V_f)E_f+V_fE_f}

Our values are given in this case as:

E = 5.17Gpa\\E_m = 3.4Gpa \\E_f = 131Gpa

Replacing,

5.17 = \frac{3.4*131}{(1-V_f)(131)+V_f*3.4}

V_f = 0.351 \rightarrow transversal

From both cases it is possible to conclude that it is not possible to produce a fiber of the specified material in a continuous and oriented manner, as long as the volume fraction is different in the different cases.

5 0
3 years ago
Yellow light (600 nm) passes through a
I am Lyosha [343]

Answer:

19.284

Explanation:

The answer is right on Accellus.

6 0
3 years ago
If the area of a circle is 58 square feet, find the circumference.
Gnom [1K]
First, you set 58= 3.14 (pi) r^2. Solving for r you get about 4.3ft. You then use this radius in the circumference equation, C=2 3.14(pi) r. 2x3.14x4.3=27.004ft. I rounded a few times along the way so your answer is B. 
8 0
3 years ago
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