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3 years ago

Which of the following are characteristics of transition metals?

Chemistry

1 answer:

Kipish [7]3 years ago

8 0

Answer:

High melting point,High density,Nonreactive

Explanation:

The following are the Properties of transition elements:

They have large charge/radius ratio. They are harder and they have high densities;.They have high melting and boiling points.They form compounds which are paramagnetic. They show variable oxidation states. They form colored ions and compounds. Compounds are formed with profound catalytic activity. Stable complexes are formed by them.

When Comparing with the alkali metals present in group 1 and the alkaline Earth metals that are present in group 2, the transition metals are considered to be much less reactive. They do not react fast with water or oxygen, which contributes to their resistance to corrosion.

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3 years ago

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What mass in grams (theoretical yield) of hydrogen is produced by the reaction of 31.3 g of

Verizon [17]

The percent yield is 74.4 %.

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First, calculate the theoretical yield of H₂O.

Theor. yield =

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2 years ago

What characteristic do the elements in group 1 share? They tend to lose one electron to become a 1+ ion. They tend to gain one e

Black_prince [1.1K]

What characteristic do the elements in group 1 share?
They tend to lose one electron to become a 1+ ion.

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3 years ago

Fill in the blanks: Repeating an experiment several times and averaging the results helps to reduce ___ ___

Juliette [100K]

Answer:

the amount of mistakes?

Explanation:

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2 years ago

at normal body temperature, 37 degree C, Kw = 2.4x10^-14. Calculate [H+] and [OH-] for a neutral solution at this temperature.

hichkok12 [17]

Answer:

1.55x10⁻⁷ = [H⁺] = [OH⁻]

Explanation:

The water equilibrium at a certain temperature is represented as follows:

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

Where Kw is represented as:

Kw = [H⁺] [OH⁻]

In a neutral solution, [H⁺] = [OH⁻], thus, at 37°C:

2.4x10⁻¹⁴ = [H⁺]²

1.55x10⁻⁷ = [H⁺]

As The water equilibrium at a certain temperature is represented as follows:

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

Where Kw is represented as:

Kw = [H⁺] [OH⁻]

In a neutral solution, [H⁺] = [OH⁻], thus, at 37°C:

2.4x10⁻¹⁴ = [H⁺]²

1.55x10⁻⁷M = [H⁺]

As [H⁺] = [OH⁻], [OH⁻] = 1.55x10⁻⁷M

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2 years ago