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mrs_skeptik [129]
3 years ago
5

What is responsible for the formation of a solution?

Chemistry
1 answer:
-BARSIC- [3]3 years ago
6 0
<span>An aqueous solution is produced when a solute dissolves in water. The biggest responsible is the water that is the solvent of substances in smaller proportion as some ions of K +, Na +, Cl -, forming true solutions. Occurs when a solute dissolves in the water solvent, the separation between the substances is atomic, molecular or ionic, depending on the solution.</span>
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Given two temperatures, 36 °F and 72 °F, which of the following correctly compares the number of opportunities for particles to
Liono4ka [1.6K]

The correct answer is "Greater at 72 °F " hope it helps

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Why is aluminium used to make outer covering of aeroplane?
iogann1982 [59]

Answer:

Aluminum is ideal for aircraft manufacture because it's lightweight and strong. Aluminum is roughly a third the weight of steel, allowing an aircraft to carry more weight and or become more fuel efficient. Furthermore, aluminum's high resistance to corrosion ensures the safety of the aircraft and its passengers.

Explanation:

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2 years ago
Balance the equation for ethane C3H6 burning in oxygen to form carbon dioxide and steam. _____C3H6 + ____ O2 ---&gt; CO2 + ____H
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2 years ago
How to classify hemicetal and acetal
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3 0
2 years ago
What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
nikdorinn [45]

Answer : The volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

Explanation :

The balanced chemical reaction will be:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

First we have to calculate the moles of Al.

\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}

Molar mass of Al = 27 g/mole

\text{Moles of }Al=\frac{55g}{27g/mol}=2mole

Now we have to calculate the moles of O_2.

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of O_2

So, 2 mole of Al react with \frac{3}{4}\times 2=0.75\times 2 moles of O_2

Now we have to calculate the volume of O_2 consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of O_2 occupies 22.4 liter volume of O_2 gas

So, 0.75\times 2 mole of O_2 occupies 0.75\times 2\times 22.4 liter volume of O_2 gas

Therefore, the volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

3 0
3 years ago
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