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mrs_skeptik [129]
3 years ago
5

What is responsible for the formation of a solution?

Chemistry
1 answer:
-BARSIC- [3]3 years ago
6 0
<span>An aqueous solution is produced when a solute dissolves in water. The biggest responsible is the water that is the solvent of substances in smaller proportion as some ions of K +, Na +, Cl -, forming true solutions. Occurs when a solute dissolves in the water solvent, the separation between the substances is atomic, molecular or ionic, depending on the solution.</span>
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If you start with 30 moles of O2, how many moles of SiO2 can you make?
Ivanshal [37]

Answer:

30moles of SiO₂

Explanation:

Given parameters:

Number of moles of O₂  = 30moles

Unknown:

Number of moles of SiO₂  = ?

Solution:

To solve this problem, we need to write the reaction expression:

       Si +  O₂  →  SiO₂  

The reaction is balanced;

      1 mole of O₂ will produce 1 mole of SiO₂

     30mole of O₂ will produce 30moles of SiO₂

7 0
3 years ago
If 8.6 L of O2 reacted with excess H2 at STP, what is volume of the gaseous water collected? @h2 (g) + O2 (g) = 2H2 O (g)
LekaFEV [45]
Note that this is occurring at STP, where 22.4L of any gas is equal to 1mol of that gas.

First, convert the liters of O₂ to moles of O₂ using the conversion factor 22.4LO₂ = 1molO₂.
8.6LO₂ × 1molO₂/22.4LO₂
= 8.6/22.4
≈ 0.3839molO₂

Next, convert moles of O₂ to moles of H₂O. In the balanced equation, the coefficients show that there are 2 moles of H₂O for every mole of O₂. So, use the conversion factor 1molO₂ = 2molH₂O.
0.3839molO₂ × 2molH₂O/1molO₂
= 0.3839 × 2
= 0.7678molH₂O

Finally, convert the moles of H₂O to liters of H₂O using the same conversion factor from before, 22.4LH₂O = 1molH₂O.
0.7678molH₂O × 22.4LH₂O/1molH₂O
= 0.7678 × 22.4
≈ 17LH₂O

So, the answer is 17 liters of gaseous water is collected! Note that its rounded to 17 because the measurement given in the problem has 2 sig figs. Hope that helps! :)
3 0
3 years ago
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Allisa [31]

Answer:

Before "true" labor begins, you might have "false" labor pains, also known as Braxton Hicks contractions.

Explanation:

8 0
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On the cooling curve below, between points Dand Ethe substance is changing from
Irina-Kira [14]
Gas to solid ( a ) is correct i think
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