Answer: The angle Ø = 26
Explanation:
The weight and the normal force of the road are the only two external forces acting on the car. A frictionless surface can only exert a force that is perpendicular to the surface. This is a normal force.
Since the car does not leave the surface of the road, the vertical components of the two external forces must be equal in magnitude and opposite in direction. Whereas ;
Horizontal component = centripetal force. While
The vertical component = Mg
Revolving the two components gives: tanØ = V^2/rg
Please find the attached file for the solution
Answer:
Explanation:
First, the instant associated to the angular displacement is:
Roots of the second-order polynomial are:
Only the first root is physically reasonable.
The angular velocity is obtained by deriving the angular displacement function:
The angular acceleration is obtained by deriving the previous function:
The resultant linear acceleration on the rim of the disk is:
D = 110 m, t = 5 s
v o = 110 cs : 5 m = 22 m/s
-------------------------------------
v = v o - a t
v = 0 m/s, v o = 22 m/s, t = 4 s
0 = 22 - 4 a
4 a = 22
a = 22 : 4
a = 5.5 m/s²
g = 9.80 m/s²
9.80 : 5.5 = 0.56
Answer:
The magnitude of its acceleration is 5.5 m/s or 0.56 g.
Answer:
Explanation:
The direction of force will be in upward direction making an angle of θ with the vertical .
Reaction force R = mg - F cosθ
Friction force = μR
= .36 (mg - F cosθ )
Horizontal component of applied force
= F sinθ
For equilibrium
F sinθ = .36 (mg - F cosθ)
F sinθ + .36 F cosθ =.36 mg
F (sinθ + .36 cosθ) = .36 mg
F R( cosδsinθ +sinδ cosθ) = .36 mg ( Rcosδ = 1 . Rsinδ= .36 )
F R sin( θ+δ ) = . 36 mg
F = .36 mg / Rsin( θ+δ )
For minimum F , sin( θ+δ ) should be maximum
sin( θ+ δ ) = sin 90
θ+ δ = 90
Rsinδ / Rcosδ = .36
δ = 20⁰
θ = 70⁰ Ans
Answer:
V(t1-t0)
Explanation:
Moving 'uniformly' means constant velocity (speed). the formula for constant speed motion is 
=( change in position/ change in time)
where,
V is speed
given in the statement :
change in time = t = t1-t0
let the constant speed be ' V '
disance = X = X1-X0
applying the above mentioned formula: V = 
V = X/t
X = Vt
the distance X1-X0 = Vt =V(t1-t0)
