Question

When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. If 2.5 mol of aluminum nitrate is added to the same amount of water, by how much will the boiling point be changed? Use 3 – 4 sentences to explain your answer.
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Answer 1

Answer is: boiling point will be changed by 4°C.

Chemical dissociation of aluminium nitrate in water: Al(NO₃)₃ → Al³⁺(aq) + 3NO⁻(aq).

Change in boiling point: ΔT =i · Kb · b.

Kb - molal boiling point elevation constant of water is 0.512°C/m, this the same for both solution.

b -  molality, moles of solute per kilogram of solvent., this is also same for both solution, because ther is same amount of substance.

i - Van't Hoff factor.

Van't Hoff factor for sugar solution is 1, because sugar do not dissociate on ions.

Van't Hoff factor for aluminium nitrate solution is approximately 4, because it dissociates on four ions (one aluminium cation and three nitrate anions). So ΔT is four times bigger.

Answer 2

The answer should be 4°C....