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dimulka [17.4K]
4 years ago
7

6. What electrolyte can be used to electrolyze water?

Chemistry
2 answers:
saw5 [17]4 years ago
6 0

Answer:

6. A

7. B

8. B

Explanation:

In the electrolysis of water, a small amount of an electrolyte is added, usually an acid solution. This assists the dissociation of water into ions during the electrolysis. Hydrogen and oxygen are obtained as products of the electrolysis.

In the electrolysis of brine, chlorine is preferentially discharged compared to the hydroxide ion due to position in the electrochemical series.

During electroplating, the metal to be plated acts as the cathode while the plating metal acts as the anode.

Neporo4naja [7]4 years ago
3 0
1. D
2. D
3. B
Just took the quiz and and I got these answers right.
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Hh

Explanation:

Bb

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Which statement best describes organs in an organ system? A. Each organ does part of a larger job. B. Each organ can perform onl
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The correct answer is -  A. Each organ does part of a larger job.

Explanation:

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A group of organs makes an organ system to perform a particular but large function in the organism for its survival. An example of the organ in an organ system is the heart in the cardiovascular system. The heart is an organ that pumps the blood out of the heart to the various part of the cardiovascular system such as lungs, arteries, and veins so it can take nutrients and oxygen to various parts carried by the blood.

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Which molecule has a nonpolar covalent bond?
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8 0
4 years ago
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A student prepares a 1.8 M aqueous solution of 4-chlorobutanoic acid (C2H CICO,H. Calculate the fraction of 4-chlorobutanoic aci
Kruka [31]

Answer:

Percentage dissociated = 0.41%

Explanation:

The chemical equation for the reaction is:

C_3H_6ClCO_2H_{(aq)} \to C_3H_6ClCO_2^-_{(aq)}+ H^+_{(aq)}

The ICE table is then shown as:

                               C_3H_6ClCO_2H_{(aq)}  \ \ \ \ \to  \ \ \ \ C_3H_6ClCO_2^-_{(aq)} \ \ +  \ \ \ \ H^+_{(aq)}

Initial   (M)                     1.8                                       0                               0

Change  (M)                   - x                                     + x                           + x

Equilibrium   (M)            (1.8 -x)                                  x                              x

K_a  = \frac{[C_3H_6ClCO^-_2][H^+]}{[C_3H_6ClCO_2H]}

where ;

K_a = 3.02*10^{-5}

3.02*10^{-5} = \frac{(x)(x)}{(1.8-x)}

Since the value for K_a is infinitesimally small; then 1.8 - x ≅ 1.8

Then;

3.02*10^{-5} *(1.8) = {(x)(x)}

5.436*10^{-5}= {(x^2)

x = \sqrt{5.436*10^{-5}}

x = 0.0073729 \\ \\ x = 7.3729*10^{-3} \ M

Dissociated form of  4-chlorobutanoic acid = C_3H_6ClCO_2^- = x= 7.3729*10^{-3} \ M

Percentage dissociated = \frac{C_3H_6ClCO^-_2}{C_3H_6ClCO_2H} *100

Percentage dissociated = \frac{7.3729*10^{-3}}{1.8 }*100

Percentage dissociated = 0.4096

Percentage dissociated = 0.41%     (to two significant digits)

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3 years ago
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BTW IT IS SCIENCE
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The answer is A warm air rises cool air sinks

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3 years ago
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