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3 years ago

Which of the following is evidence that groundwater cause erosion and deposition

Chemistry

1 answer:

defon3 years ago

4 0

Answer:You didn't provide examples

Explanation: Groundwater can cause erosion under the surface as it moves through the soil. During the movement an acid is formed which what causes erosion and deposition.

Hope that helps

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What is the empirical formula of the compound whose molecular formula is P4O10

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The empirical formula is the lowest reduced ration of the atoms present. In this case, it is P2O5

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Which of the following substances is a chemical that is made only by chemists?

Rainbow [258]

Answer:

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Explanation:

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3 years ago

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Sunny_sXe [5.5K]

1. Homolo.gous

2. Hete.rozygous

3. Reces.sive, Domin.ant

4. n

5. N

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Gaseous ethane (CH,CH,) will react with gaseous oxygen (02) to produce gaseous carbon dioxide (CO2) and gaseous water (H,0). Sup

BigorU [14]

Answer: The mass of $CO_2$ produced is 12.32 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

For ethane:

Given mass of ethane = 4.21 g

Molar mass of ethane = 30 g/mol

Putting values in equation 1, we get:

$\text{Moles of ethane}=\frac{4.21g}{30g/mol}=0.140mol$

For oxygen gas:

Given mass of oxygen gas = 31.9 g

Molar mass of oxygen gas= 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{31.9g}{32g/mol}=0.997mol$

The chemical equation for the combustion of ethane follows:

$2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O$

By stoichiometry of the reaction:

If 2 moles of ethane reacts with 7 moles of oxygen gas

So, 0.140 moles of ethane will react with = $\frac{7}{2}\times 0.140=0.49mol$ of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, ethane is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of ethane produces 4 moles of $CO_2$

So, 0.140 moles of ethane will produce = $\frac{4}{2}\times 0.140=0.28mol$ of $CO_2$

We know, molar mass of $CO_2$ = 44 g/mol

Putting values in above equation, we get:

$\text{Mass of }CO_2=(0.28mol\times 44g/mol)=12.32g$

Hence, the mass of $CO_2$ produced is 12.32 g

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3 years ago

I don’t understand this question someone please help

egoroff_w [7]

The answer is 49.97.

3 0

3 years ago