Answer:
Explanation:
The molecular formula for Potassium Dichromate is K2Cr2O7. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Potassium Dichromate, or 294.1846 grams.
Note that rounding errors may occur, so always check the results.
Answer:
B. Changes in the Moon's visibility.
Explanation:
The moon's shifting of position makes it "appear" as being smaller or bigger. This is simply because the moon is rotating and the sun's light shines on a certain area of the moon, and depending on where we are on the Earth is how the moon looks or appears to our perspective.
Answer:
cierra los ojos que me vengo o me vengo
cierra los ojos que me vengo o me vengo
Explanation:
cierra los ojos que me vengo o me vengo cierra los ojos que me vengo o me vengo cierra los ojos que me vengo o me vengo cierra los ojos que me vengo o me vengo cierra los ojos que me vengo o me vengo cierra los ojos que me vengo o me vengo
The question is incomplete, here is the complete question:
At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1 M⁻¹s⁻¹
Suppose a vessel contains SO₃ at a concentration of 1.44 M. Calculate the concentration of SO₃ in the vessel 0.240 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits.
<u>Answer:</u> The concentration of 
in the vessel after 0.240 seconds is 0.24 M
<u>Explanation:</u>
For the given chemical equation:
The integrated rate law equation for second order reaction follows:
![k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%5Cleft%20%28%5Cfrac%7B1%7D%7B%5BA%5D%7D-%5Cfrac%7B1%7D%7B%5BA%5D_o%7D%5Cright%29)
where,
k = rate constant = 
t = time taken= 0.240 second
[A] = concentration of substance after time 't' = ?
![[A]_o](https://tex.z-dn.net/?f=%5BA%5D_o)
= Initial concentration = 1.44 M
Putting values in above equation, we get:
![14.1=\frac{1}{0.240}\left (\frac{1}{[A]}-\frac{1}{1.44}\right)](https://tex.z-dn.net/?f=14.1%3D%5Cfrac%7B1%7D%7B0.240%7D%5Cleft%20%28%5Cfrac%7B1%7D%7B%5BA%5D%7D-%5Cfrac%7B1%7D%7B1.44%7D%5Cright%29)
![[A]=0.245M](https://tex.z-dn.net/?f=%5BA%5D%3D0.245M)
Hence, the concentration of in the vessel after 0.240 seconds is 0.24 M
