NaOH (s) is in solid state and NaOH (aq) is an aqueous solution.
Answer:
Q= 0.21472 C
Explanation:
current is the rate of flow of charge through a wire or a circuit.
I = Q/t
Where I is current
Q is charge
t is time
Q=It
from the question, I=0.52 A , t=411 milliseconds
Q = 0.52 *411*
Q= 0.21472 C
Answer:
Atoms form chemical bonds to make their outer electron shells more stable. The type of chemical bond maximizes the stability of the atoms that form it.
Number of oxygen atoms present in 7.15×10²³ molecules of mannose are 1.92≈2 a m u .
<h3>What is mannose sugar?</h3>
D-mannose is a simple sugar found in many fruits. It is related to glucose. In some cells it occurs naturally in the body.
Mannose is a six-carbon sugar found in a variety of fruits and vegetables. This sugar is not found free in foods. It is a part of polysaccharide chains attached to a variety of proteins.
To calculate number of oxygen atoms present in 7.15×10²³ molecules of mannose-
Since,
1 molecule of oxygen=2.303×10²³ no. of atoms
Here, total number of molecules of oxygen is 6.
Therefore, 6 molecule of oxygen =6×2.303×10²³÷7.15×10²³
=1.92≈2 a m u .
Hence, the total number of oxygen atoms in 7.15×10²³ molecules of mannose is 1.92 ≈2 a m u.
Learn more about mannose sugar, here:
brainly.com/question/7008130
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Answer:
Formula Weight of gas sample = 20.1 g/mole => Neon (Ne)
Explanation:
Use Ideal Gas Law formula to determine formula weight and compare to formula weights of answer choices.
PV = nRT = (mass/fwt)RT => fwt = (mass/Volume)RT = Density x R x T
Density = 0.900 grams/L
R = 0.08206 L·atm/mole·K
T = 0.00°C = 273Kfwt = (0.900g/L)(0.08206L·atm/mole·K )(273K)
= 20.1 g/mol => Neon (Ne)