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Harrizon [31]
3 years ago
15

Which is the MOST accurate description about the habitable zone in the area around a star? A. Liquid water could exist there. B.

Liquid water cannot exist there. C. Liquid water always exists there.
Physics
1 answer:
Monica [59]3 years ago
5 0
The correct answer is
<span>A. Liquid water could exist there.

In fact, liquid water is fundamental for life. So, one of the conditions to define the habitable zone around a star is that the temperature allows the presence of liquid water.</span>
You might be interested in
Answer the following question according to formal grammatical rules.
VARVARA [1.3K]

Answer:

c

Explanation:

just trying to follow basic grammar.

5 0
2 years ago
What is the acceleration of a 349 kg object that moved with a force of 750 N?
zavuch27 [327]

Answer:

<h3>The answer is 2.15 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

where

f is the force

m is the mass

From the question we have

a =  \frac{750}{349}  \\  = 2.14899713...

We have the final answer as

<h3>2.15 m/s²</h3>

Hope this helps you

4 0
2 years ago
PLEASE HELP AND HURRY!!!!!!!!!
never [62]

Answer:

I believe the answer would be A. point x

4 0
3 years ago
LOTS OF POINTSA rocket of mass 40 000 kg takes off and flies to a height of 2.5 km as its engines produce 500 000 N of thrust.
Svetradugi [14.3K]

Answer:

i) E = 269 [MJ]    ii)v = 116 [m/s]

Explanation:

This is a problem that encompasses the work and principle of energy conservation.

In this way, we establish the equation for the principle of conservation and energy.

i)

E_{k1}+W_{1-2}=E_{k2}\\where:\\E_{k1}= kinetic energy at moment 1\\W_{1-2}= work between moments 1 and 2.\\E_{k2}= kinetic energy at moment 2.

W_{1-2}= (F*d) - (m*g*h)\\W_{1-2}=(500000*2.5*10^3)-(40000*9.81*2.5*10^3)\\W_{1-2}= 269*10^6[J] or 269 [MJ]

At that point the speed 1 is equal to zero, since the maximum height achieved was 2.5 [km]. So this calculated work corresponds to the energy of the rocket.

Er = 269*10^6[J]

ii ) With the energy calculated at the previous point, we can calculate the speed developed.

E_{k2}=0.5*m*v^2\\269*10^6=0.5*40000*v^2\\v=\sqrt{\frac{269*10^6}{0.5*40000} }\\ v=116[m/s]

8 0
2 years ago
Use the five rules to determine the validity of this categorical syllogism:
Novay_Z [31]

Question:

The five rules are;

"The middle term must be distributed in at least one premise.

If a major or minor term is distributed in the conclusion, then it must be distributed in the premises.

No syllogism can have two negative premises.

If either premise is negative, the conclusion must be negative.

No syllogism with a particular conclusion can have two universal premises."

Answer:

The categorical syllogism is invalid as it does not meet thr requirements of rule 2

Invalid because it breaks rule #2.

Explanation:

An argument whose conclusion is  implied based on the logical stipulation of the premise is a deductive argument

A  syllogism is a deductive argument that makes use of deductive reasoning to come to  conclusion, considering a number of of two or more premises which are taken to be true.

For categorical syllogism, we have

If  A is in C, then B is in C

Based on the five rules, we have

1. The middle term must be distributed at least once

Here, the middle term is all neutron stars are extremely dense hence i says something about all items in a category, therefore it is distributed

2. If a term is distributed in the conclusion, then it must be distributed in the premise.

Here, the distributed term in the conclusion are "extremely dense objects" is not distributed in the premise, therefore the categorical syllogism is invalid.

4 0
3 years ago
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