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Arisa [49]
3 years ago
7

Raindrops acquire an electric charge as they fall. Suppose a 2.4-mm-diameter drop has a charge of +18 pC, fairly typical values.

Physics
1 answer:
muminat3 years ago
3 0

To solve this problem we will apply the concepts related to the potential, defined from the Coulomb laws for which it is defined as the product between the Coulomb constant and the load, over the distance that separates the two objects. Mathematically this is

V = \frac{kq}{r}

k = Coulomb's constant

q = Charge

r = Distance between them

q = 18 pC \rightarrow q = 1.8*10^-11 C

d = 2.4mm \rightarrow r = 1.2 mm = 1.2*10^-3 m

Replacing,

V = \frac{kq}{r}

V = \frac{ (9*10^9)*(1.8*10^{-11})}{(1.2*10^{-3})}

V = 135 V

Therefore the potential at the surface of the raindrop is 135 V

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A container is filled to a depth of 19.0 cm with water. On top of the water floats a 31.0-cm-thick layer of oil with specific gr
IceJOKER [234]

Answer:

Absolute pressure of the oil will be 102822.8 Pa  

Explanation:

We have given height h = 31 cm = 0.31 m

Acceleration due to gravity g=9.8m/sec^2

Specific gravity of oil = 0.600

So density of oil \rho =0.6\times 1000=600kg/m^3

We know that absolute pressure is given by P=P_0+\rho gh, here P_0=1.01\times 10^5Pa

So absolute pressure will be equal to P=1.01\times 10^5+600\times 9.8\times 0.31=102822.8Pa

So absolute pressure of the oil will be 102822.8 Pa

6 0
4 years ago
In recent years, assistive technologies have been developed to give people with disabilities equal access to resources. Apex
rosijanka [135]

Answer: as the public need for equal access for people with disabilities became understood, laws were enacted to mandate assistive technologies inclusion in almost all public spaces

Explanation: I just took the test but my teachers a füçkįñg čūńt so don't know if the this will help

3 0
4 years ago
If a total force exerted by water in a container with a bottom area of 3 square meters is 900 newtons, what's the water pressure
bekas [8.4K]

Answer:

300 Pa

Explanation:

P=F/A

= 900/3

= 300 Pa

8 0
2 years ago
What is the magnitude and direction of an electric field that exerts a 2.00×10−5N upward force on a –1.75μC charge?
Sophie [7]

Answer:

E = - 11.4 N/C, Directed Downward

Explanation:

Force = 2.00×10⁻⁵N , charge Q = –1.75μC = -1.75 ×10⁻⁶ C

To Find: Electric Field E = ? and Direction=?

Sol

we Have

E = F / Q

E = 2.00×10⁻⁵N /  -1.75 ×10⁻⁶ C

E = - 11.428 N/C (-ve sign shows that it is Negative Electric Field around a negative charge and will attract the Positive Field)

As given an upward force on negative charge so direction of the Electric Filed will be Downward (as Electric field is opposite to direction of force on negative charge)

3 0
3 years ago
If the ladybug has a mass of 6.0 kg and is at a distance r = 1 m, find her A) velocity, B) centripetal acceleration, and C) cent
Dominik [7]

a) 3.14 m/s

b) 9.9 m/s^2

c) 59.4 N

Explanation:

a)

The relationship between angular velocity and linear velocity for an object in circular motion is given by:

v=\omega r

where

\omega is the angular velocity

v is the linear velocity

r is the distance between the object and the axis of rotation

For the ladybug in this problem, we have:

r = 1 m (distance)

\omega=3.14 rad/s (angular velocity)

So, its linear velocity is

v=(3.14)(1)=3.14 m/s

b)

The centripetal acceleration of an object in circular motion is given by the equation

a=\frac{v^2}{r}

where

v is the linear velocity

r is the distance between the object and the axis of rotation

The centripetal acceleration represents the radial acceleration of the object.

For the ladybug in this problem, we have:

v = 3.14 m/s (linear velocity)

r = 1 m (distance)

So, the centripetal acceleration is

a=\frac{3.14^2}{1}=9.9 m/s^2

c)

The centripetal force for an object in circular motion is given by

F=ma

where

m is the mass of the object

a is the centripetal acceleration of the object

The centripetal force is the radial inward force that keeps the object in circular motion.

For the ladybug in this problem we have

m = 6.0 kg (mass)

a=9.9 m/s^2 (centripetal acceleration)

So, the centripetal force is

F=(6.0)(9.9)=59.4 N

6 0
3 years ago
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