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Fantom [35]
3 years ago
6

Oil enters a 100-mm-diameter pipe steadily with a velocity of 5 m/s. The gage pressure in the pipe at A and B is 80 kPa. The den

sity of the oil is 900 kg/m3. Neglect gravitational effects. Determine the reaction force exerted on the elbow by the couplings at A and B. Please clearly define the coordinate system and the control volume.

Physics
1 answer:
Marat540 [252]3 years ago
4 0

Answer:

Explanation:

Solutiiiin is in the attachment below

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A runner wants to run 12.0 km . Her running pace is 8.2 mi/hr . How many minutes must she run? Express your answer using two sig
Hunter-Best [27]

Answer:

53 minutes

Explanation:

To solve this problem, we need to use common proportions to convert.

= 11.7km * 1mi/1.61km * 1hr/8.2mi * 60min/hr

≈ 53 minutes

Best of LUck!

5 0
2 years ago
A 1369.4 kg car is traveling at 28.9 m/s when the driver takes his foot off the gas pedal. It takes 5.1 s for the car to slow do
Darya [45]

Answer:

F = 2389.603 N

Explanation:

Given:

Mass m = 1,369.4 kg

Initial velocity u = 28.9 m/s

Final velocity v = 20 m/s

Time t = 5.1 s

Find:

Net force

Computation:

a = (v - u)/t

a = (20 - 28.9)/5.1

a = -1.745 m/s²

F = ma

F = (1369.4)(1.745)

F = 2389.603 N

7 0
2 years ago
What is the momentum of a 50-kilogram ice skater gliding across the ice at a speed of 5 m/s? (1 point)
serious [3.7K]
Momentum is a term used to quantify the motion of an object has. It is calculated as the the product of the object's mass and the velocity. It is expressed as:

Momentum = m x v
Momentum = 50 kg x 5 m/s
Momentum = 250 kg m/s

Therefore, the correct answer is the last option.
3 0
3 years ago
Read 2 more answers
You slide a hockey puck across the ice in a hockey rink
REY [17]

Answer-

mk thats kool.

8 0
2 years ago
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Please help me, this is a physics test.
sweet-ann [11.9K]

Answer:

a = 2 [m/s²]

Explanation:

To be able to solve this problem we must make it clear that the starting point when the time is equal to zero, the velocity is 5 [m/s] and when three seconds have passed the velocity is 11 [m/s], this point is the final point or the final velocity.

We can use the following equation.

v_{f}=v_{o}+a*t\\

where:

Vf = final velocity = 11 [m/s]

Vo = initial velocity = 5 [m/s]

a = acceleration [m/s²]

t = time = 3 [s]

11 = 5 + a*3\\6=3*a\\a= 2[m/s^{2} ]

4 0
2 years ago
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