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BaLLatris [955]
3 years ago
7

If light at 193 nm from an argon–fluoride laser is incident on a gold metal surface, electrons with kinetic energy of 1.80  10–

19 J are produced. What is the work function of gold in kJ/mol? What is the minimum wavelength of light in nm required to produce photoelectrons from gold (zero kinetic energy)?

Chemistry
1 answer:
MAVERICK [17]3 years ago
3 0

Answer:work function= 8.2×10-19J

Minimum wavelength of light required= 2.4×10-7m

Explanation:

The wavelength of incident light was given as 193nm. We have to convert this to meters and have 193×10-9m. Then we use it to find the energy of incident photon E. When E is found we now apply Einstein photoelectric equation to obtain the work function Wo since the kinetic energy of photoelectrons is known as 1.8×10-19J.

From this work function. We can obtain the minimum wavelength of light required. All these steps are shown in the image attached.

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3 0
3 years ago
26 Milkweed contains a poison known as cardenolides. Monarch butterflies eat the milkweed plant and hold on to this toxic compou
Amanda [17]

Cardenolides, with the chemical formula CH₁₈C₂₀H₁₅CHCO₂ have (D) 23 carbon atoms, 34 hydrogen atoms, and 2 oxygen atoms.

Milkweed contains a poison known as cardenolides. The chemical formula for cardenolides CH₁₈C₂₀H₁₅CHCO₂.

The subscripts in the formula represent the atomicities, that is the number of atoms of each element in each part of the formula.

We can calculate the total number of atoms of each element by adding its atomicities.

<h3>Carbon atoms</h3>

C =  1 + 20 + 1 + 1 = 23

<h3>Hydrogen atoms</h3>

H = 18 + 15 + 1 = 34

<h3>Oxygen atoms</h3>

O = 2

Cardenolides, with the chemical formula CH₁₈C₂₀H₁₅CHCO₂ have (D) 23 carbon atoms, 34 hydrogen atoms, and 2 oxygen atoms

Learn more: brainly.com/question/13348838

5 0
3 years ago
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
adell [148]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is 523.2 kJ.

Explanation:

Step 1:

CaC_2(s) + 2H_2O(g)\rightarrow C_2H_2(g) + Ca(OH)_2(s),\Delta H_1=414.0 kJ...[1]

Step 2 :

6C_2H_2(g) + 3CO_2(g) + 4H_2O(g)\rightarrow 5CH_2CHCO_2H(g) \Delta H_2=132.0kJ..[2]

Adding 6 × [1] and [2]:

6CaC_2(s) + 12H_2O(g)\rightarrow 6C_2H_2(g) + 6Ca(OH)_2(s)

6C_2H_2(g)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)

we get :

6CaC_2(s) + 8H_2O(g)+3CO_2(g)\rightarrow 5CH_2CHCO_2H(g)+ 6Ca(OH)_2(s),\Delta H'=?

\Delta H'=6\times \Delta H_1+\Delta H_2

\Delta H'=6\times 414.0 kJ+132.0kJ

\Delta H'=2,626 kJ

Energy released on formation of 5 moles of acrylic acid = 2,626 kJ

Energy released on formation of 1 mole of acrylic acid:

\frac{ 2,626 kJ}{5 } = 523.2 kJ

7 0
4 years ago
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