Answer:
<h2>The answer is 9 kg</h2>Explanation:
The mass of an object can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>9 kg</h3>Hope this helps you
If launched at the right speed, what could eventually happen to objects launched from Newton's theoretical cannon on the top of
1 answer:
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b and e are the largest and equal in magnitude.
A and d are next. aR = (3rad/s2)R = 3R
c is zero. wR = v = 0; Angular acceleration is zero.
<h3>What is angular acceleration?</h3>- The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second. Therefore, = d d t. Rotational acceleration is another name for angular acceleration.
- Angular velocity divided by acceleration time can be used to define angular acceleration. (t). As an alternative, use pi times the drive speed (n) divided by the acceleration time (t) times 30. Radians per second squared (Rad/sec2) is the standard SI unit for rotational acceleration resulting from this equation.
- To calculate angular velocity, we can use one of three formulas. The definition itself provides the first. Theta = position angle, t = time, and w = angular velocity, where w = angular velocity, theta = position angle, and t = time. Angular velocity is the rate of change of an object's position angle with respect to time.
- The symbol for angular acceleration is, and it is measured in rad/s2, or radians per second square.
If two items are equal, show them as equal in your ranking. If a quantity is equal to zero, show that fact in your ranking:
b and e are the largest and equal in magnitude.
A and d are next. aR = (3rad/s2)R = 3R
c is zero. wR = v = 0; Angular acceleration is zero.
To learn more about angular acceleration, refer to:
#SPJ4
Answer:
0.9999986*c
Explanation:
The ship would travel 2.54*10^7 light years, which means that at a speed close to the speed of light the trip would take 2.54*10^7 years from the point of view of an observer on Earth. However from the point of view of a passenger of that ship it will take only 70 years if the speed is close enough to the speed of light.
Where
Δt is the travel time as seen by a passenger
Δt' is the travel time as seen by someone on Earth
v is the speed of the ship
c is the speed of light in vacuum
We can replace the fraction v/c with x
It would need to travel at 0.9999986*c