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Shtirlitz [24]
3 years ago
14

If launched at the right speed, what could eventually happen to objects launched from Newton's theoretical cannon on the top of

a mountain?
Physics
1 answer:
Nadusha1986 [10]3 years ago
4 0
If the speed is higher than the orbital velocity, but not high enough to leave Earth altogether (lower than the escape velocity), it will continue revolving around Earth along an elliptical orbit. (D) for example horizontal speed of 7,300 to approximately 10,000 m/s for Earth.
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What displacement in cm would occur with a 75 N/m spring if you placed a 300 N weight on the spring?
ollegr [7]

Surface tension=75N/m

Weight=300N

\\ \bull\tt\longmapsto Surface\:Tension=\dfrac{Weight}{Displacement}

\\ \bull\tt\longmapsto Displacement=\dfrac{Weight}{Surface\:Tension}

\\ \bull\tt\longmapsto Displacement=\dfrac{300}{75}

\\ \bull\tt\longmapsto Displacement=4m

\\ \bull\tt\longmapsto Displacement=400cm

6 0
3 years ago
The molecular weight of carbon dioxide (CO2) is 44.00 a.m.u., and the molecular weight of propane gas (C3H8) is 44.10 a.m.u. Thu
Nina [5.8K]

The molecular weight of carbon dioxide (CO2) is 44.00 a.m.u., and the molecular weight of propane gas (C3H8) is 44.10 a.m.u. Thus CO2 diffuses_______ C3H8.

Slower Than

Faster Than

The Same As

Slower than

6 0
3 years ago
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Explain what it's meant by refraction of light
ozzi
The definition of refraction is<span> the bending of </span>light<span> as </span>it<span> passes from one substance to another. I hope this helps you, have a great day!</span>
5 0
3 years ago
A student wearing frictionless in-line skates on a horizontal surface is pushed by a friend with a constant force of 47 N. How f
Novosadov [1.4K]

Answer:

7.53 m

Explanation:

Force, F = 47 N

initial velocity, u = 0

Final kinetic energy, Kf = 354 J

Let the distance traveled by the student is s.

According to the work energy theorem,

Work done by all forces = Change in kinetic energy

Force x distance = final kinetic energy - initial kinetic energy

F x s = kf - ki

47 x s = 354

s = 7.53 m

4 0
3 years ago
A nearsighted person cannot see objects further away than 10 m clearly. This person wants to be able to see objects 300 m away w
icang [17]

Answer:

d.-10.3m

Explanation:

Note for short sightedness the focal length is negative

Let do be object distance=10m

And di= image distance=-300m

Using lens formula

F=do*di/do-di= 10*300/10-300=-10.3m

4 0
3 years ago
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