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sveticcg [70]
3 years ago
11

Solve integral (2x-5)⁷ dx​

Mathematics
1 answer:
trapecia [35]3 years ago
4 0

Answer: 128x^7dx-2240x^6dx+16800x^5dx-70000x^4dx+175000x^3dx-262500x^2dx+218750xdx-7812

Step-by-step explanation:

1) Expand : (2x-5\right)^7dxquad 128x^7dx-2240x^6dx+16800x^5dx-70000x^4dx+175000x^3dx-262500x^2dx

2) Distribute Parentheses

3) Apply your minus/plus rules

+(-a)= -a

128x^7dx-2240x^6dx+16800x^5dx-70000x^4dx+175000x^3dx-262500x^2dx+218750xdx-78125dx

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