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sveticcg [70]
3 years ago
11

Solve integral (2x-5)⁷ dx​

Mathematics
1 answer:
trapecia [35]3 years ago
4 0

Answer: 128x^7dx-2240x^6dx+16800x^5dx-70000x^4dx+175000x^3dx-262500x^2dx+218750xdx-7812

Step-by-step explanation:

1) Expand : (2x-5\right)^7dxquad 128x^7dx-2240x^6dx+16800x^5dx-70000x^4dx+175000x^3dx-262500x^2dx

2) Distribute Parentheses

3) Apply your minus/plus rules

+(-a)= -a

128x^7dx-2240x^6dx+16800x^5dx-70000x^4dx+175000x^3dx-262500x^2dx+218750xdx-78125dx

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Which statement compares the two numbers correctly?
Over [174]

Answer:

D) six hundred twenty-nine thousandths > six times one tenth plus three times one hundredth plus two times one thousandth

629000>8403     TRUE

Step-by-step explanation:

A) six times one tenth plus three times one hundredth plus two times one thousandth < six hundred twenty-nine thousandths

8,403.00

<629000 FALSE

B) six times one tenth plus three times one hundredth plus two times one thousandth = six hundred twenty-nine thousandths

8403= 629000   FALSE

C) six hundred twenty-nine thousandths < six times one tenth plus three times one hundredth plus two times one thousandth

629000<8403 FALSE

D) six hundred twenty-nine thousandths > six times one tenth plus three times one hundredth plus two times one thousandth

629000>8403     TRUE

Hope This Helps!!!

5 0
2 years ago
Can anyone help me out with this answer?
Bogdan [553]

9514 1404 393

Answer:

  7×10⁻¹ +6×10⁻² +5×10⁻³

Step-by-step explanation:

Place value in any place-value number system increases by a factor of the base for each place to the left of the "decimal" point. It is reduced by a factor of the base for each place to the right of the "decimal" point.

For base-10 numbers, the powers of 10 are -1, -2, -3, ... as you go to the right of the decimal point. Hence the number 0.765 decomposes as ...

  7×10⁻¹ +6×10⁻² +5×10⁻³

3 0
2 years ago
6x-12+2x=3+8x-15 please
andreev551 [17]
6x-12+2x=3+8x-15 \\ \\ 8x-12=8x-12 \\ \\ 8x-8x=-12+12 \\ \\ \boxed{0=0}
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200,000 + 80,000 + 3,000 + 900 + 80
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3 years ago
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