Answer:
5.71 rad/s , 54.55 rev/min
Explanation:
mass of disc, m = 60 kg
diameter of disc = 35 cm
radius of disc, r = 17.5 cm
Rotational kinetic energy, K = 15 J
Let I be the moment of inertia of the disc and ω be the angular speed of the disc.
The moment of inertia of the disc is given by
I = 0.5 x 60 x 0.175 x 0.175 = 0.92 kg m^2
Kinetic energy
ω = 5.71 rad/s
ω = 5.71 / 2π rev /s
ω = 0.909 rev /s
ω = 0.909 x 60 rev / min = 54.55 rev/min
Answer:
1 (pitcher), 2 (catcher), 3 (first baseman), 4 (second baseman), 5 (third baseman), 6 (shortstop), 7 (left fielder) 8 (center fielder), and 9 (right fielder)
Explanation:
There are nine fielding positions in baseball. Each position conventionally has an associated number, for use in scorekeeping by the official score
Answer:
pull to activate something
Explanation:
Thank you for your question, what you say is true, the gravitational force exerted by the Earth on the Moon has to be equal to the centripetal force.
An interesting application of this principle is that it allows you to determine a relation between the period of an orbit and its size. Let us assume for simplicity the Moon's orbit as circular (it is not, but this is a good approximation for our purposes).
The gravitational acceleration that the Moon experience due to the gravitational attraction from the Earth is given by:
ag=G(MEarth+MMoon)/r2
Where G is the gravitational constant, M stands for mass, and r is the radius of the orbit. The centripetal acceleration is given by:
acentr=(4 pi2 r)/T2
Where T is the period. Since the two accelerations have to be equal, we obtain:
(4 pi2 r) /T2=G(MEarth+MMoon)/r2
Which implies:
r3/T2=G(MEarth+MMoon)/4 pi2=const.
This is the so-called third Kepler law, that states that the cube of the radius of the orbit is proportional to the square of the period.
This has interesting applications. In the Solar System, for example, if you know the period and the radius of one planet orbit, by knowing another planet's period you can determine its orbit radius. I hope that this answers your question.