Answer:
See below in the explanation section the Matlab script to solve the problem.
Explanation:
prompt='enter the first weight w1: ';
w1=input(prompt);
wd1=double(w1);
prompt='enter the second weight w2: ';
w2=input(prompt);
wd2=double(w2);
prompt='enter the third weight w3: ';
w3=input(prompt);
wd3=double(w3);
prompt='enter the fourth weight w4: ';
w4=input(prompt);
wd4=double(w4);
prompt='enter the first weight w5: ';
w5=input(prompt);
wd5=double(w5);
x=[wd1 wd2 wd3 wd4 wd5]
format short
Answer:
Explanation:
If the fixed ladder will reach more than twenty-four (24) feet above a lower level, you as the employer are required to incorporate a personal fall arrest or ladder safety system into the installation of the ladder. For reference, this requirement is cited in OSHA Section 1910.28(b)(9)(i).
If the total length of the climb on a fixed ladder equals or exceeds 24 feet (7.3 m), the ladder must be equipped with ladder safety devices; or self-retracting lifelines and rest platforms at intervals not to exceed 150 feet (45.7 m); or a cage or well and multiple ladder sections with each ladder section not
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Problem-Solving Tip: When cutting an FBD through an axial member, assume that the internal force is tension and draw the force arrow directed away from the cut surface. If the computed internal force value turns out to be a positive number, then the assumption of tension is confirmed.