Since g is constant, the force the escaping gas exerts on the rocket will be 10.4 N
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What is Escape Velocity ?</h3>
This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.
Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.
To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters
- Mass (m) of the rocket 0.25 Kg
- Initial velocity u = 15 m/s
- Final Velocity v = 40 m/s
- Gravitational field intensity g = 9.8N/kg
The force the gas exerts of the rocket = The force on the rocket
The rate change in momentum of the rocket = force applied
F = ma
F = m(v - u)/t
F = 0.25 x (40 - 15)/0.6
F = 0.25 x 41.667
F = 10.42 N
Since g is constant, the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.
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Answer:
V = L A = L pi R^2 volume of wire
V = 50 cm * .01 cm^2 = .5 cm^3
d(density) = 3.5 gm / .5 cm^3 = 7.0 gm/cm^3
A micrometer caliper could measure the diameter of the wire.
Answer:
A
Explanation:
warm air rises creating low presure
cold air sinks creating high presure
so this means that temprature is realated to presure.
The wave characteristic that is the same for both waves is wavelength.
- Two waves with the same frequency will also have the same wavelength, amplitude, speed, and period. When two waves are travelling at the same frequency, it denotes that their duration and amplitude are also the same.
- When two waves of the same frequency and amplitude interfere constructively, their peaks and troughs align as shown in diagram A above. As a result, the original waves' amplitude is doubled, resulting in a sound wave that is twice as loud.
Thus, Equal frequencies are shared by two waves moving through the same region in the same direction.
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