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kap26 [50]
3 years ago
11

An object moving at a velocity of 32m/s slows to a stop in 4 seconds. What was its acceleration?

Physics
2 answers:
Romashka [77]3 years ago
6 0

Answer:

8m/s

Explanation:

a=d/t

a=32/4

a=8 m/s

LiRa [457]3 years ago
5 0

Answer:

-8m/s^2

Explanation:

initial velocity(u)=32m/s

Final velocity(v)=0

Time(t)=4seconds

Acceleration(a)=?

v=u+axt

0=32+ax4

-32=4a

a=-32/4

a=-8m/s^2

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Time period between  t=2  until  t=5  is  (5 - 2) = 3 seconds.

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