All categories

4 years ago

The compound XCl is classified as Ionic if x represents the element?

2 answers:

6 0

Well since chlorine upon receiving a valence electron from the X element, we would know that the element would be a metal, based on the charge of Cl, after it receives a valence electron is -1, the metal would have to give 1 valence electron as well, and thus the possible elements can be any metal within the group 1 of the periodic table of elements. Lithium, Potassium etc.

Studentka2010 [4]4 years ago

6 0

Answer:

X belongs to the alkali metals which can be lithium, sodium, potassium, rubidium and caesium.

Explanation:

Ionic bond: This type of bond is formed when there is a complete transfer of electrons from one element to another element. In this bonding one element is always a metal and another is a non-metal.

Chlorine is the element of group 17 and third period. The atomic number of chlorine is 17 and the symbol of the element is Cl.

The electronic configuration of the element chlorine is:-

$1s^22s^22p^63s^23p^5$

Thus, chlorine need one electron to become stable and form ionic bond.

Also, the ionic compound has the formula XCl which means that the valency of X is +1.

<u>Thus X belongs to the alkali metals which can be lithium, sodium, potassium, rubidium and caesium.</u>

You might be interested in

Which of the following substances would you predict to have the highest DHvap? Group of answer choices CH3CH2CH2CH3 CH3CH2OH HF

Katyanochek1 [597]

Answer:

a) $CH_3CH_2CH_2CH_3$

Explanation:

In this question we have the following answer choices:

a) $CH_3CH_2CH_2CH_3$

b) $CH_3CH_2OH$

c) $HF$

d) $CH_3Cl$

e) $HOCH_2CH_2OH$

We have to remember the relationship between intermolecular forces and vapor pressure. If we have stronger intermolecular forces we will have less vapor pressure because the molecules have more interactions between them, so, the molecules will prefer to stay in a liquid state rather than a gaseous state. Now, we have to check each molecule:

a) $CH_3CH_2CH_2CH_3$ (Van der waals interactions)

b) $CH_3CH_2OH$ (Hydrogen bonding)

c) $HF$ (Hydrogen bonding)

d) $CH_3Cl$ (Dipole-dipole interaction)

e) $HOCH_2CH_2OH$ (Hydrogen bonding)

For molecules b, c and e we have <u>hydrogen bond to a heteroatom</u> (O, N, S, or P). In this case oxygen, therefore we will have <u>hydrogen bonding </u>interactions (a very strong interaction). So, we can discard these ones.

In molecule e, we have "Cl" bond to a "C" therefore we will have the presence of a <u>dipole</u> (due to the <u>electronegativity difference</u>). If we have a dipole, we will have a <u>dipole-dipole interaction</u> (a strong interaction, less than hydrogen bonding but still is a strong interaction).

In molecule a, we have only <u>Van der Waals interactions</u> because in this molecule we have only carbon and hydrogen atoms bonded by single bonds. So, we will have a n<u>on-polar molecule</u>. These interactions are the weakest interactions of all the molecules given. So, <u>if we have weaker interactions the molecules can be converted to a gas state more easily and we have more vapor pressure. </u>

7 0

3 years ago

To reflect about a problem means to ask yourself about any possible ‘what ifs.’ Please select the best answer from the choices p

Naily [24]

The answer is true true true

4 0

3 years ago

Read 2 more answers

How can a solid dissolved in water be separated from the water?.

Alex73 [517]

Answer:

Evaporation

Explanation:

Boiling the water will make it evaporate, leaving the solid at the bottom of the solution

3 0

3 years ago

A certain photon has a frequency of 634x1012 Hz. What is the photon's wavelength in a vacuum? Enter your answer in nm (x10-9 m).

Shtirlitz [24]

<h3>Answer:</h3>

4.73 × 10^4 m

<h3>Explanation:</h3>

From the question;

Frequency of the photon = 634 × 10^12 Hz

We are required to calculate the wavelength of the photon.

We need to know the relationship between wavelength and frequency of a wave.

The relationship between f and λ is given by;

c = fλ

Where c, is the speed of light, 2.998 × 10^8 m/s

Therefore, to get the wavelength we rearrange the formula such that;

λ = c ÷ f

= 2.998 × 10^8 m/s ÷ 634 × 10^12 Hz

= 4.73 × 10^-5 m

But we require wavelength in nm

1 M = 10^9 nm

Therefore;

Wavelength = 4.73 × 10^-5 m × 10^9 nm/m

= 4.73 × 10^4 m

Hence, the photon's wavelength is 4.73 × 10^4 m

4 0

3 years ago

13.3 g of benzene (C6H6) is dissolved in 282 g of carbon tetrachloride. What is the molal concentration of benzene in this solut

Verizon [17]

Answer:

0.605 molal

Explanation:

molality is the amount of solute in a particular mass of solvent.

lets calculate the amount of benzene solute.

mass of benzene= 13.3g

molar mass of C6H6= 12*6 +1*6 =72+7=78g/mol

amount of benzene= mass/molar mass

=13.3/78

=0.1705mol

molality= amount of solute/mass of solvent in kg

mass of solvent=282g=0.282kg

molality = 0.1705/0.282

=0.605 molal

6 0

3 years ago