D would be correct (i did this Assessment today)<span />
Central "carbon" atom
2 oxygen atoms
held together by "covalent" bonds
has a "1s2 2s2 2px1 2py1 2pz0" electron
geometry
carbon atom is "sp" hybridized
The answer you're looking for is: a wave.
nabr + cacl2 are the products
Answer:
For this experiment we are going to take plate 1 as the control plate, so, in it there will be just E. coli in LB/agar; in plate 2, we are going to put E. coli in LB/agar and some ampicillin. Then, we have to wait for the E. coli colonies to form. After a while, the E. coli growth can be compared on both plates and determine if ampicillin affects or not the E. coli colonies.
Explanation:
If the ampicillin affects negatively E. coli colonies, we are going to observe that in plate 1 (control plate) there are E. coli colonies growing, but in plate 2, there is no E. coli colonies or, at least, there is a fewer number of colonies on it. If ampicillin doesn't affect E.coli, plate 1 (control) and plate 2 (ampicillin experiment) are going to be similar in number of colonies.
