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Stels [109]
3 years ago
7

Two spherical asteroids have the same radius R. Asteroid 1 hasmass M and asteroid 2 has mas 2M. The two asteroids are releasedfr

om rest with distance 10R between their centers. What is thespeed of each asteroid just before they collide?
Physics
1 answer:
gtnhenbr [62]3 years ago
6 0

Answer:

 v_1 =\sqrt{\dfrac{16GM}{15R}}

 v_2 =\sqrt{\dfrac{4GM}{15R}}

Explanation:

given,

mass of asteroid 1 = M

mass of asteroid 2 = 2M

radius of two asteroid = R

Distance between the asteroid = 10 R

Speed of the asteroid before collision = ?

using conservation of momentum

M u + 2M u' = M v₁ + 2 M v₂

initial speed of asteroid is equal to zero

0 = v₁ + 2 v₂

v₁ = -2 v₂

using conservation of momentum

initial potential energy is converted into potential energy and the kinetic energy of both the asteroids.

 \dfrac{GM(2M)}{10R}=\dfrac{GM(2M)}{2R}+\dfrac{1}{2}Mv_1^2 + \dfrac{1}{2}(2M)v_2^2

 \dfrac{GM(2M)}{10R}-\dfrac{GM(2M)}{2R}=\dfrac{1}{2}M(-2v_2)^2 + \dfrac{1}{2}(2M)v_2^2

 6v_2^2 = \dfrac{8GM}{5R}

 v_2 =\sqrt{\dfrac{4GM}{15R}}

now,

 v_1 =-2\sqrt{\dfrac{4GM}{15R}}

 v_1 =\sqrt{\dfrac{16GM}{15R}}

hence, the velocity of asteroid are

 v_1 =\sqrt{\dfrac{16GM}{15R}}

 v_2 =\sqrt{\dfrac{4GM}{15R}}

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Answer:

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Explanation:

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f=\dfrac{v}{\lambda}\\\\f=\dfrac{45}{3}\\\\f=15\ Hz

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Answer: It’s False hope this helps

Explanation:

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This equation can be differentiated with respect to the radius of change, that is

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At the same time since Newton's second law we know that:

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4 years ago
Steam enters an adiabatic turbine at 5 MPa and 4500C and leaves at a pressure of 1.4 MPa. Determine the work output of the turbi
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8 0
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